The mean of the given sample data is 210, and the standard deviation is 7.937.
Given size 'n' = 300
The population proportion 'p' = 0.7
Let 'x' be the random variable of the binomial distribution
a) mean of the binomial distribution = n p = 300 × 0.7
μ = 210
b) variance of the binomial distribution
⇒ n p q
⇒ 300 × 0.7 ×0.3
⇒ σ² = 63
The standard deviation of the binomial distribution:
⇒ √n p q = √63 = 7.937
Thus, the mean of the given sample data is 210, and the standard deviation is 7.937.
Learn more about the standard deviation here:
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The question seems to be incomplete the correct question would be:
describe the sampling of p hat. Assume that the size of the population is 25000 n= 300 p=0.7 a) Determine the mean of the sampling distributionb) Dtermine the standard deviation of the sampling distribution
Answer:
Solving for x;
2x + 85 + 5x + 29 = 930
combine like terms:
7x + 114 = 930
-114 -114
7x = 816
/7 /7
x = 116.57, now we replace the x with it's actual value:
∠ZT = 2(116.57) + 85 = 318.14°
∠ZV = 5(116.57) + 29 = 611.85°, lets double check if they both equal 930;
318.14 + 611.85 = 929.99, which is close to 930 so we are correct.
Answer:
now ion kno what type of math this is btfu but
no 4 should equal dbc which is anwer 4
hope i helped
Answer:
30 weeks
Step-by-step explanation:
7.25 x 20 = 1 WEEK
1 WEEK= 145$
4,350 divided by 145=30
30 weeks
(-5,1) hope this helps you
