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topjm [15]
3 years ago
5

Can someone help me with this question thanks (:

Mathematics
2 answers:
Musya8 [376]3 years ago
7 0
The tree is 12 ft tall
aleksley [76]3 years ago
4 0

Answer: The tree has a shadow of 48 feet

Step-by-step explanation:

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A cable company charges $50 for installation and $80 per month for service. Choose the equation that shows the total cost, c, in
Serhud [2]
The answer would be c
7 0
3 years ago
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40% of students enjoy playing Among us. If 100 students enjoy playing Among us, how many students are there?
Luba_88 [7]

Answer:

250

Step-by-step explanation:

40%= 100

10%=25

100%= 250

6 0
3 years ago
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Which of the following equations is equivalent to y + 3 = -4(x - 2)?
Allushta [10]

Answer:

D. y= -4x +5

Step-by-step explanation:

  • The equation y+3=-4(x-2) can be transformed by doing some algebra.
  • If we solve the second term of the equation -4(x-2)= 8 - 4x, then we have  y+3=8-4x (this is done by distributing the multiplication into the two terms: remember that the product of -4x(-2)=+8 because the product of two negative numbers is a possitive number).
  • Then, by subtracting both sides 3, we have y=5-4x. Rearranging terms in the right side, we have y=-4x+5, which is option D.
6 0
3 years ago
Find the area of an equi. triangle with an apothem of 2ft
Kaylis [27]

Answer:

(1/2)(4√3ft)(6 ft) = 12√3ft2.

Step-by-step explanation:

For an equilateral triangle, the apothem is 1/3 of the height, so the height is 3 times 2 ft or 6 ft.

The base of the equilateral triangle is the apothem times 2√3 or 2ft times 2√3 = 4√3ft.

So the area of the triangle is (1/2)(base)(height) or

(1/2)(4√3ft)(6 ft) = 12√3ft2.

5 0
3 years ago
Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
SVEN [57.7K]

The given function is

h(x)=-16x^2+300x+20

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.

Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

h=-\frac{b}{2a}

Where a = -16 and b = 300.

\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

\begin{gathered} k=-16(9.375)^2+300(9.375)+20 \\ k=-1406.25+2812.5+20=1426.25 \end{gathered}

Hence, the maximum height is 1426.25 feet.

At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

t=2\cdot9.375=18.75

Hence, the rocket hits the ground after 18.75 seconds.

6 0
1 year ago
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