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tankabanditka [31]
3 years ago
11

2x

Mathematics
1 answer:
laiz [17]3 years ago
3 0

Answer:

7

Step-by-step explanation:

2x² - 28x + 98 = 0

x² - 14x + 49 = 0

(x - 7)² = 0

x = 7

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Initially, there were only 86 weeds in the garden. The weeds grew at a rate of 29% each week. The following function represents
Orlov [11]

Step-by-step answer:

The base of the exponential function is 1.29 for 7 days, as in

f(x) = 86*(1.29)^x

The new rate for days can be calculated by dividing x by 7 (where x remains the number of weeks), namely

f(x) = 86*1.29^(x/7)

Using the law of exponents, b^(x/a) = b^(x*(1/a)) = (b^(1/a))^x

we simplify by putting b=1.29, a=7 to get

f(x) = 86*(1.29^(1/7))^x

f(x) = 86*(1.037)^x      since 1.29^(1/7) evaluates to 1.037

Rounding 1.037 to 1.04 we get a (VERY) approximate function

f(x) = 86 * (1.04^x)

1.04 is very approximate because 1.04^7 is supposed to get back 1.29, but it is actually 1.316, while 1.037^7 gives 1.2896, much closer to 1.29.

7 0
3 years ago
Read 2 more answers
What is the product?
Lerok [7]
You just have to multiply straight across. Multiply the numerators for the new numerator, and the denominators for the new denominator.
5*3=15
4*8=32
15/32 is the answer (b).
5 0
3 years ago
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If the triangle measure 180 degrees. What is the missing angle?
max2010maxim [7]

Answer:

116

Step-by-step explanation:

36+28=64

180-64=116

3 0
3 years ago
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Find the value of the X to the nearest tenth 57* 6
Otrada [13]

Answer

6 is the nearest tenth it did not say ten it said ten-th

4 0
3 years ago
A geometric sequence has first term 1/9 and common ratio 3. Which is the first term of the sequence which exceeds 1000?
Svetach [21]
a_{n}= \frac{1}{9}  (3)^{n-1}
(We know this from a=1/9 and r=3)
Simplifying this, we get:
\frac{1}{9} (3)^{-1} (3)^n

Since we're finding the first term that exceeds 1000, let's set it equal to 1000.

\frac{1}{27}(3)^n=1000
Multiplying both sides by 27
3^n=27000

log_{3}27000=n

n≈9.2

We have to round n up, since if n=9, the value would be <1000.
Therefore n=10. Substituting n=10,
\frac{1}{27}3^{10}
=2187

Therefore the first term that exceeds 1000 is 2187, and it is the 10th term
3 0
3 years ago
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