All categories

3 years ago

What are the first three terms of the sequence represented by the recursive formula

Mathematics

2 answers:

Artyom0805 [142]3 years ago

5 0

So
an=n^2-a(n-1)
the nth term is equal to n^2-previous term

5th term=5^2-previous term
14.25=25-previousterm
previousterm=10.75=4th term

4th term=4^2-previous term
10.75=16-previous term
previousterm=5.25=3rd term

3rd term=3^2-previous term
5.25=9-previous term
3.75=previus term=2nd
so we see it is 2nd option

Nadusha1986 [10]3 years ago

3 0

I think it is the second option

You might be interested in

The Hu family goes out for lunch, and the price of the meal is $58. The sales tax on the meal is 7%, and the family also leaves

soldier1979 [14.2K]

The total price would be $73.66. If you can't tell, I determined the sales tax and tip by making the percent into a decimal (20% is 0.20, 7% 0.07, etc) and multiplied each onw by the original price, then added my tax and tip to the original price.

7 0

3 years ago

Show that a = −1 + √3i and b = 2 satisfy 1/a+b=1/a + 1/b

Zarrin [17]

Answer:

LHS = $\frac{1 - \sqrt3i}{4}$ = RHS = $\frac{1 - \sqrt3i}{4}$

Step-by-step explanation:

Data provided in the question:

a = −1 + √3i and b = 2

to prove:

$\frac{1}{a+b}=\frac{1}{a} + \frac{1}{b}$

Considering the LHS

⇒ $\frac{1}{a+b}$

substituting the value of a and b, we get

⇒ $\frac{1}{−1 + \sqrt3i+2}$

⇒ $\frac{1}{1 + \sqrt3i}$

on multiplying and dividing by conjugate ( 1 - √3i )

we get

$\frac{1}{1 + \sqrt3i}\times\frac{1 - \sqrt3i}{1 - \sqrt3i}$

$\frac{1 - \sqrt3i}{(1^2 - (\sqrt3i)^2}$

$\frac{1 - \sqrt3i}{1 + 3}$ (as (√i)² = -1 )

$\frac{1 - \sqrt3i}{4}$

Now,

considering the RHS

$\frac{1}{a} + \frac{1}{b}$

substituting the value of a and b, we get

⇒ $\frac{1}{-1 + \sqrt3i} + \frac{1}{2}$

⇒ $\frac{2\times1 + ( -1 + \sqrt3i)\times1}{(-1 + \sqrt3i)\times2}$

⇒ $\frac{2 + ( -1 + \sqrt3i)}{(-1 + \sqrt3i)\times2}$

⇒ $\frac{1 + \sqrt3i}{(-1 + \sqrt3i)\times2}$

now,

on multiplying and dividing by conjugate ( -1 - √3i )

we get

$\frac{1 + \sqrt3i}{(−1 + \sqrt3i)\times2}\times\frac{-1 - \sqrt3i}{-1 - \sqrt3i}$

$\frac{1 + \sqrt3i}{(−1 + \sqrt3i)\times2}\times\frac{-1( 1 + \sqrt3i)}{-1 - \sqrt3i}$

$\frac{(1 + \sqrt3i}^2\times(-1){((-1)^2 - (\sqrt3i)^2)\times2}$

$\frac{(1^2 + (\sqrt3i)^2+2(1)(\sqrt3i)\times(-1)}{(1 + 3)\times2}$

$\frac{(1 - 3 + 2\sqrt3i)\times(-1)}{(4)\times2}$

$\frac{(-2 + 2\sqrt3i)\times(-1)}{(4)\times2}$

$\frac{-2( 1 - 2\sqrt3i)\times(-1)}{(4)\times2}$

$\frac{( 1 - 2\sqrt3i)}{(4)}$

Since, LHS = RHS

hence satisfied

3 0

3 years ago

What is the explicit rule for this geometric sequence?

ladessa [460]

<span>a4 = 3*4 = 12. Answer: 3,6,9,12. 3) an = 3n – 5 a1 = 3*1-5 = -2 a2 = 3*2 – 5 = 1 a3 = 3*3-5 = 4 a4 = 3*4 – 5 = 7 Answer: -2,1,4,7. 5) an = 3n a1 = 31= 3 ... 21) an = (-1)n; a50. Answer: a50 = (-1)50 = 1. 23) an = ;a12. Answer: #25-40: write an expression for the nth term of the sequence. 25) 2,4,6,8,10…. Answer: an = 2n ...</span><span>
</span>

5 0

4 years ago

54,872 in expanded form

lina2011 [118]

Answer:

54,000+800+70+2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

PLS HELP ME I WILL GIVE BRAINLESS] Solve the problems. AA + 5 JoJo Seaweed walks at a constant rate d. able shows the relationsh

musickatia [10]