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kirza4 [7]
4 years ago
7

Y=-6x+15 Y=4x-15 solve by elimination

Mathematics
1 answer:
Nikitich [7]4 years ago
6 0
X=3 and y=−3 is the answer
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PLEASE HELP 5 POINT ASSIGNMENT (LEASE TO GREATEST PROBLEM)
marshall27 [118]

Answer:

1/2 < 3/5 < 2/3 < 5/6

Step-by-step explanation:

Using the given inputs:

1/2 5/6 2/3 3/5

The least common denominator (LCD) is: 30.

Rewriting as equivalent fractions with the LCD:

1/2 5/6 2/3 3/5

15/30 25/30 20/30 18/30

Sorting this table by the numerators of the equivalent fractions in order from least to greatest:

1/2 3/5 2/3 5/6

15/30 < 18/30 < 20/30 < 25/30

Therefore, the sorted inputs in order from least to greatest is:

1/2 < 3/5 < 2/3 < 5/6

6 0
3 years ago
GEOMETRY PROBLEM HELP ME PLEASE
Anon25 [30]

Answer:

18. x=31

19.x=15

20. a. x=5 WXY= 28

b. YXZ=28

c. WXZ=56

6 0
3 years ago
Read 2 more answers
Antonio and Candice had a race. Their distances past a particular landmark as the race progressed can be represented by linear
Alisiya [41]

Answer:Antonio had a head start of 3 meters

Step-by-step explanation:I took the test

5 0
4 years ago
How to solve the logarithmic equation.
Anna007 [38]
Using logarithmic laws: log(a) + log(b) = log(ab)

log₄ (x + 9) + log₄ (x + 21) = log₄ [(x + 9)(x + 21)] = 3

Since we want the equation in terms of x, the next intuitive step is take 4 to the power of both sides, because the left hand side will simplify easily.

4^{log_4 (x + 9)(x + 21)} = 4^{3}
(x + 9)(x + 21) = 64
x^{2} + 9x + 21x + 189 = 64

Solving the quadratic we get:
x^{2} + 30x + 125 = 0
(x + 5)(x + 25) = 0

x = -5, -25

BUT, for the logarithmic equation to be defined, x > -9, so x≠ -25
Thus, the only solution is x = -5.
7 0
3 years ago
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
ivolga24 [154]

<u>Answer:</u>

<h2>A = 15 u²</h2>

<u>Explanation:</u>

according to the coordinates the triangles is right at the pair (2, -3)

the area of the triangle = height × base × 1/2

the <u>height</u> is the line passing through the pairs (-1, 6) and (2, -3)

h² = (2-(-1))²+(-3-6)²

h² = 3² + (-9)²

h² = 9 + 81

h² = 90

h = √90

the <u>base</u> is the line passing through the pairs (5, -2) and (2, -3)

b² = (2-5)²+(-3-(-2))²

b² = 3² + (-3+2)²

b² = 9 + 1

b² = 10

b = √10

A = h×b×1/2

A = √90×√10×1/2

A = √900×1/2

A = 30×1/2

A = 15 u²

5 0
3 years ago
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