All categories

2 years ago

If R is the midpoint of TS, TR = 5x - 12, and RS = 3x + 8, find TS.

Mathematics

2 answers:

Mademuasel [1]2 years ago

8 0

Answer:

Step-by-step explanation:

GenaCL600 [577]2 years ago

6 0

Answer:

5x -12 = 3x +8 (set the two = each other because they are the same length)

2x- 12= 8 (subtract 3x from both sides)

2x = 20 (add 12 to both sides)

x=10 (what x= for both expressions)

5(10) -12 (plug it into the first one to see what the length is and to see they're =

50 - 12 ( I already multiplied, now subtract)

38 (what the length of TR is)

3(10) +8 (plug it in again but into the other expression)

30+8 (multiply and add)

38 (the two have the same answer, so the x-value is correct.)

38+38= 76 (add the lengths of RS and TR and you get the length of TS)

Step-by-step explanation:

I hope this helps :)

You might be interested in

What is 32 / 10 equal

kupik [55]

Answer:

3.2. The decimal point moves left once because there's only one 0

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The table gives an inequality and a number to multiply both sides of the inequality by. Identify the new, true inequality.

EastWind [94]

Answer:

its B

Step-by-step explanation:

4 0

3 years ago

What is the greatest common factor (gcf) for 26 and 78? 6 13 26 3 2

saul85 [17]

For this case we have that by definition, the GCF of two numbers is the biggest common factor that divides both numbers without leaving residue. We find the factors:

26: 1,2,13,26

78: 1,2,3,6,13,26

Thus, the GCF of both numbers is 26

Answer:

Option C

8 0

3 years ago

The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle

AVprozaik [17]

Answer:

Length of rectangle is 31 yards and Width is 24 yards.

Given:

The length of a rectangle is 7 more than the width.
The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

$\\ \: \: \: \: \pink{ \dashrightarrow \: \: \: \: \sf { \underbrace{Area_{(Rectangle)} = Length × Width }}} \\ \\$

On Substituting the required values, we get;

$\\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x = 24 \: or \: - 31 \\ \\$

As we know that width of the rectangle can't be negative. So x = 24

Hence,

Width of rectangle = x = 24 yards
Length of the rectangle = x + 7 = 31 yards

$\therefore$ Length of rectangle is 31 yards and Width is 24 yards.

8 0

2 years ago

Email used a total of 7 1half

Gala2k [10]

13 - 5 5/6
= 12 6/6 - 5 5/6
= 7 1/6

hope it helps

7 0

3 years ago