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4 years ago

5

Determine whether the relation is a function.

1 answer:

Alexxx [7]4 years ago

5 0

Answer:

function

Step-by-step explanation:

every x value has only 1 y value

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Help Please......<br>...<br>...<br>..

vfiekz [6]

Answer:

$9\frac{3}{2}$ smallest

$27\frac{1}{3}$

$125\frac{2}{3}$ largest

Step-by-step explanation:

First change the mixed numbers into an improper fractions.

$9\frac{3}{2}$ = $\frac{21}{2}$ 9 x 2 = 18 + 3 = 21

$27\frac{1}{3}$ = $\frac{82}{3}$ 27 x 3 = 81 + 1 = 82

$125\frac{2}{3}$ = $\frac{377}{3}$ 125 x 3 = 375 + 2 = 377

Find the least common denominator.

2 and 3 have 6

$\frac{21}{2}$ = $\frac{63}{6}$ smallest

$\frac{82}{3}$ = $\frac{164}{6}$ medium

$\frac{377}{3}$ = $\frac{754}{6}$ largest

4 0

3 years ago

A particle moves along line segments from the origin to the points (2, 0, 0), (2, 4, 1), (0, 4, 1), and back to the origin under

Shkiper50 [21]

The work is equal to the line integral of $\vec F$ over each line segment.

Parameterize the paths

from (0, 0, 0) to (2, 0, 0) by $\vec r_1(t)=t\,\vec\imath$ with $0\le t\le2$ ,
from (2, 0, 0) to (2, 4, 1) by $\vec r_2(t)=2\,\vec\imath+4t\,\vec\jmath+t\,\vec k$ with $0\le t\le1$ ,
from (2, 4, 1) to (0, 4, 1) by $\vec r_3(t)=(2-t)\,\vec\imath+4\,\vec\jmath+\vec k$ with $0\le t\le2$ , and
from (0, 4, 1) to (0, 0, 0) by $\vec r_4(t)=(4-4t)\,\vec\jmath+(1-t)\,\vec k$ with $0\le t\le1$

The work done by $\vec F$ over each segment (call them $C_1,\ldots,C_4$ ) is

$\displaystyle\int_{C_1}\vec F\cdot\mathrm d\vec r_1=\int_0^2\vec0\cdot\vec\imath\,\mathrm dt=0$

$\displaystyle\int_{C_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(t^2\,\vec\imath+24t\,\vec\jmath+32t^2\,\vec k)\cdot(4\,\vec\jmath+\vec k)\,\mathrm dt=\int_0^1(96t+32t^2)\,\mathrm dt=\frac{176}3$

$\displaystyle\int_{C_3}\vec F\cdot\mathrm d\vec r_3=\int_0^2(\vec\imath+(24-12t)\,\vec\jmath+32\,\vec k)\cdot(-\vec\imath)\,\mathrm dr=-\int_0^2\mathrm dt=-2$

$\displaystyle\int_{C_4}\vec F\cdot\mathrm d\vec r_4=\int_0^1((1-t)^2\,\vec\imath+2(4-4t)^2\,\vec k)\cdot(-4\,\vec\jmath-\vec k)\,\mathrm dt=-2\int_0^1(4-4t)^2\,\mathrm dt=-\frac{32}3$

Then the total work done by $\vec F$ over the particle's path is 46.

8 0

4 years ago

Write an equation that represents the line.<br> Use exact numbers.

spin [16.1K]

Answer:

-4 and 2

Step-by-step explanation:

The exact numbers of that position is -4 and 2

3 0

3 years ago

Suppose we have 14 boxes of pastries (each box of a different flavor), each with a scone and a muffin inside. For example, one b

Nat2105 [25]

Answer:

Step-by-step explanation:

5 0

3 years ago

20.) Marc had to walk to the grocery store which was exactly 50 meters from his house. So far he has walked exactly 21 meters. W

Sloan [31]

Marc has walked 42 % of the journey

<h3>How to calculate the percentage ? </h3>

The total miles is 50 meters

Marc has walked for 21 meters

The percentage he has walked can be calculated as follows

= 21/50 × 100

= 0.42 × 100

= 42

Hence the percentage of mile Marc walked is 42%

Read more on percentage here

brainly.com/question/20340402?referrer=searchResults

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5 0

1 year ago