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ki77a [65]
3 years ago
5

Did you mean: a dolphin was swimming 28 meters below the ocean's surface it changed its depth to avoid a predator and ended up 2

1 meters below the surface
Mathematics
1 answer:
Vesna [10]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

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the population of a town is 1,03.500 if 56%of the population is male find the number of females in the town
bija089 [108]
The population you gave isn't formatted correctly so I'll solve the problem assuming you mean 103,500.

First we find the number of males from the percentage given:

0.56 * 103500 = 57960 males

Subtract the number of males from the total population to get the number of females:

103500 - 57960 = 45540 females

You could solve the problem by finding the percentage of females first. Since there are 56% males, that means there are 100-56 = 44% females.

0.44 * 103500 = 45540

The answer is 45540.




8 0
3 years ago
Simplify using the distributive property, Show all work -2(x - 5) + 4(9 + x).
zzz [600]
-2(x - 5) + 4(9 + x)
-2x + 10 + 36 + 4x
=2x + 46
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4 years ago
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Nookie1986 [14]
The answer for  Group A. is  0.080 or 0.08
the answer for Group B. 1.07 or 1.070
5 0
3 years ago
If a gas cost $3.29 per gallon and I fill my tank with 12.6 gallons then how much will I be charged
Lelu [443]

Answer:

Step-by-step explanation:

So you do 3.29*12.6=41.454. Since we are dealing with money we round to get $41.45

6 0
3 years ago
Read 2 more answers
Someone answer this question I know your reading this.
IgorC [24]

Answer: A.

Step-by-step explanation:

To answer this, you must first understand what fractional exponents mean.

An exponent of 1 is simply the base itself. 7^1 = 7.

An exponent of 2 is squaring the base: 7^2 = 49.

An exponent of 1/2 is taking the square root of the base: 7^(1/2) = sq root of 7

Therefore, an exponent of 1/3 is taking the cube root of the base.

In this case, the base is 2.03 * t.

Therefore, this can be represented as the cube root of the product of 2.03 and the age of the mammal, so the answer is A.

3 0
3 years ago
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