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kipiarov [429]
3 years ago
15

If a gas cost $3.29 per gallon and I fill my tank with 12.6 gallons then how much will I be charged

Mathematics
2 answers:
NikAS [45]3 years ago
8 0

Answer:

$41.454

Step-by-step explanation:

<u>Step 1:  Make an expression</u>

3.29 * 12.6 = x

<u>Step 2:  Multiply</u>

<u />3.29 * 12.6 = x

41.454 = x

Answer:  $41.454

Lelu [443]3 years ago
6 0

Answer:

Step-by-step explanation:

So you do 3.29*12.6=41.454. Since we are dealing with money we round to get $41.45

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If Luke pushes his sister in a wagon down the driveway that is 14 meters long and it takes 22 Newtons of force, how much work di
erica [24]

Hello!

The answer is:

Luke did a work of 308N.m or 308 Joules.

<h2>Why?</h2>

When a force is applied on a object making it to move covering a distance we call it "work". The movement caused by the force, will follow the same direction that the force.

We can calculate the work done by using the following equation:

Work=Force*distance*Cos(\alpha)

Where,

Work is the transferred energy.

Force, is the force applied to the object.

Distance, is the distance covered due to the applied force.

α, is the angle at the work is done.

We are given the following information to calculate the work done:

Force=22N\\Distance=14m

So, substituting the given information into the equation to calculate work, we have:

Work=Force*distance\\Work=22N*14m=308N.m

Hence, we have that Luke did a work of 308N.m or 308 Jouls.

Have a nice day!

3 0
3 years ago
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statuscvo [17]

Answer:

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8 0
3 years ago
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In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
A closed container has 5.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10−24 grams.
MatroZZZ [7]

Answer:

The correct option is the last one (0,84 grams, because (5.04 × 1.67) × (10^23 x 10^-24) = 8.4168 x 10^-1))

Step-by-step explanation:

The first step is to think that you have to multiply the number of atoms for the weight of each atom.

When you work with scientific notation, you should solve the operation for numbers and for the ten base. In this case you solve 5.04 x 1.67 and then the product of the ten bases. For this product you have to sum the exponents of the ten base 23 + (-24) = -1.

Summarizing.... 5.04 x 10^23 x 1.67 x 10^-24 = (5.04 x 1.67) x (10^23x10^-24)  ⇒ 5.04 x 10^23 x 1.67 x 10^-24 = 8.4168 x 10^-1

⇒ 5.04 x 10^23 x 1.67 x 10^-24 = 0,84168.

4 0
3 years ago
SOMEONE PLEASE EXPLAIN THIS TO ME
Angelina_Jolie [31]

17.5 = x

Step-by-step explanation:

1st you add 85 and 55 since those to angles are congruent (means similar) to 8x

2nd you get 140 after adding then

3rd since the angles are congruent you just divide the 140 by 8 to get the value of x

6 0
3 years ago
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