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Stolb23 [73]
3 years ago
9

Find the slope of the line using the points indicated. Then write an equation for the line.

Mathematics
1 answer:
Kryger [21]3 years ago
5 0
The slope of the line is -2/2
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Solve the proportion 60/n = 20/7
IrinaK [193]

Answer:

The answer is zero there is no solving.

Step-by-step explanation:

cause you do

60/n=20/7, and then you move all the terms to the left

now it is: 60/2-(20/7)=0

the domain to this is n=0

add the numbers and variables together and get

60/n-(+20/7)=0 now get rid of the parentheses and now you got

60/n-20/7=0

and all that is 0

kinda hope this help lol

8 0
2 years ago
Ax +3= 6<br> Solve for x.
k0ka [10]

Answer:

Step-by-step explanation:

Let's solve for a.

ax+3=6

Step 1: Add -3 to both sides.

ax+3+−3=6+−3

ax=3

Step 2: Divide both sides by x.

ax /x = 3 /x

a= 3 /x

Answer:

a= 3 /x

 

3 0
3 years ago
Read 2 more answers
Solve the following exponential equations.<br> 10^(x+1) − 10^(x−1) = 1287
Rudiy27

Answer:x=2.114

Step-by-step explanation:

Given

10^{x+1}-10^{x-1}=1287

10\times 10^x-\frac{10^x}{10}=1287

Let 10^x=y

10y-\frac{y}{10}=1287

\frac{100y-y}{10}=1287

99y=1287\times 10

y=\frac{12870}{99}=130

10^x=130

Taking \logboth sides

x\log (10)=\log (130)

x=\frac{\log (130)}{1}

x=2.114

7 0
3 years ago
Which expression represents the sixth term in binomial expansion (2a-3b)^10
AysviL [449]

Therefore the sixth term in the binomial expansion is=-{10}C_5(2a)^{5} (3b)^5

Step-by-step explanation:

Given

(2a -3b)^{10}

=^{10}C_0 (2a)^{10} + ^{10}C_1(2a)^9(-3b)+^{10}C_2(2a)^8(-3b)^2+...............+^{10}C_10(-3b)^{10}

So,

T_{n+1}= ^{10}C_n(2a)^{(10-n)} (-3b)^n

T_6=T_{(5+1)} =^{10}C_5(2a)^{10-5} (-3b)^5

Therefore the sixth term in the binomial expansion is= {10}C_5(2a)^{10-5} (-3b)^5

                                                                                         =-{10}C_5(2a)^{5} (3b)^5

3 0
3 years ago
Helpppppppppppppppppppppppppppp
guapka [62]

Answer:

<em>(3a + 8b) (3a - 8b)</em>

Step-by-step explanation:

The difference in two perfect "squares" in the scenario would be the (8b) and (-8b).

The 3a would stay consistent through out the whole.

7 0
3 years ago
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