Answer:
48 cm^2
Step-by-step explanation:
<em>Problem:</em>
A composite figure is divided into two congruent trapezoids, each with a height of 4 cm. 2 trapezoids. Both trapezoids have base lengths of 10 cm and 6 cm, and a height of 4 cm. Trapezoid area: A = (1/2)(b1 + b2)h What is the area of this composite figure? 32 cm squared 40 cm squared 64 cm squared 80 cm squared
<em>Solution:</em>
The problem gives you all the information you need.
area of trapezoid = A = (1/2)(b1 + b2)h
b1 = 10 cm
b2 = 6 cm
h = 4 cm
Also, keep in mind the composite figure is made up of two trapezoids, so after we find the area of one trapezoid, we will double it to find the total area.
A = (1/2)(10 cm + 6 cm)(4 cm) = 24 cm^2
The area of 1 trapezoid is 24 cm^2.
The total area = 2 * 24 cm^2 = 48 cm^2
