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vladimir1956 [14]

2 years ago

9

Find the perimeter and area of the polygon with the given vertices C (4,0) D (4,7) E (8,7) F(8,0)

1 answer:

Dafna11 [192]2 years ago

3 0

The perimeter would be 7+7+4+4 or 14+8 which equals 22 and the area would be 7x4 which is 28

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B) Raj bought $3.63 worth of raisins.<br> What was the mass in grams? Give two<br> possible answers.

Romashka [77]

Answer:

how much is 1 gram of raisins worth in money

Step-by-step explanation:

6 0

3 years ago

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Solve the following differential equation: y" + y' = 8x^2

PtichkaEL [24]

Answer:

$y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$

Step-by-step explanation:

Let's find a particular solution. We need a function of the form $y= ax^3+bx^2+cx+d$ such that

$y'= 3ax^2+2bx+c$ and

$y''= 6ax+2b$

$y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2$

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a = 8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is $y_p= \frac{8}{3}x^3-8x^2+16x$ .

Now, let's find the solution $y_p$ of the homogeneus equation $y''+y'=0$ with the method of constants coefficients. Let $y=e^{\lambda x}$

$y'=\lambda e^{\lambda x}$

$y''=\lambda^2e^{\lambda x}$

then $\lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0$

$e^{\lambda x}(\lambda +\lambda^2)= 0$

$(\lambda +\lambda^2)= 0$

$\lambda (1+\lambda)= 0$

$\lambda =0$ and $\lambda)= -1$ .

So, $y_h = C_1 + C_2e^{-x}$ and the solution is

$y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$ .

5 0

3 years ago

Mimi has 16 more bouncy balls than leah.

Lynna [10]

I would think it would be r

4 0

3 years ago

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Serjik [45]

You would divide 3/5 by 4/1 so then that would mean you keep change flip so its 3/5 times 1/4 which is equal to 3/20 each person or friend would get

3 0

3 years ago

The box plots show the data distributions for the number of customers who used a coupon each hour for two days of a store sale.

lidiya [134]

Answer:

2

Step-by-step explanation:

We can observe from the box plot the medians of both days.

The line in the middle of the box plot represents the median.

The median for Day 1 is: 6

The median for Day 2 is: 8

We have to find the difference between medians of both box plots so the difference is:

8 - 6 = 2

The difference between the medians is 2 ..

4 0

3 years ago

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