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3 years ago

Find the perimeter and area of the polygon with the given vertices C (4,0) D (4,7) E (8,7) F(8,0)

Mathematics

1 answer:

Dafna11 [192]3 years ago

3 0

The perimeter would be 7+7+4+4 or 14+8 which equals 22 and the area would be 7x4 which is 28

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If The 3rd term of an A.S is and 5th term is . What is an A.P?

guajiro [1.7K]

Answer:

you have to mention the 3rd term of AP and 5th term of AP. Then only we can find the AP.

8 0

3 years ago

Find x, GH, and HI <br> .

ruslelena [56]

Given that GI = 53, and
• GH = 3x - 11
• HI = 2x + 4

We can establish the following equality statement to solve for x:

GH + HI = GI
3x - 11 + 2x + 4 = 53

Combine like terms:
5x - 7 = 53

Add 7 to both sides:
5x - 7 + 7 = 53 + 7
5x = 60

Divide both sides by 5 to solve for x:
5x/5 = 60/5

x = 12

Substitute the value of x into the equality statement to verify if it is the correct value for x:

GH + HI = GI
3x - 11 + 2x + 4 = 53

3(12) - 11 + 2(12) + 4 = 53
36 - 11 + 24 + 4 = 53
53 = 53 (True statement. Thus, x = 12 is the correct value).

Therefore:
GH = 3x - 11
GH = 3(12) - 11
GH = 25

HI = 2x + 4
HI = 2(12) + 4
HI = 28

Please mark my answers as the Brainliest, if you find this helpful. :)

6 0

2 years ago

Suppose that we have a sample space S5 {E1, E2, E3, E4E4E, E5, E6, E7}, where E1, E2, . . ., E7 denote the sample points. The fo

VashaNatasha [74]

Answer:

P(A) = 0.4 ; P(B) = 0.50 ; P(C) = 0.60 ; P(A u B) = 0.65 ; P(A n B) = 0.25 ;

A and C are mutually exclusive ;

0.5

Step-by-step explanation:

S = {E1, E2, E3, E4, E5, E6, E7}

P(E1) = .05, P(E2) = .20, P(E3) = .20, P(E4) = .25, P(E5) = .15, P(E6) = .10, and P(E7) = .05

Let:

A{E1,E4,E6}

B{E2,E4,E7}

C{E2,E3,E5,E7}

P(A) = 0.05 + 0.25 + 0.10 = 0.40

P(B) = 0.20 + 0.25 + 0.05 = 0.50

P(C) = 0.20 + 0.20 + 0.15 + 0.05 = 0.60

AUB = {E1, E2, E4, E6, E7}

P(A u B) = 0.05 + 0.20 + 0.25 + 0.10 + 0.05 = 0.65

AnB = {E4}

P(A n B) = 0.25

A and C are mutually exclusive if AnC = ∅

A n C = ∅

Hence, A and C are mutually exclusive.

B complement = B' = {E1, E3, E5, E6}

P(B') = 0.05 + 0.20 + 0.15 + 0.10 = 0.5

5 0

3 years ago

A rectangular garden has an area of 24 square meters. The width is 8 meters less than twice the length. Find the dimensions of t

OLEGan [10]

Answer:

Length: 6 m

Width: 4 m

Step-by-step explanation:

Area: 24 $m^{2}$

Width: 2L - 8 m

Length: ?

Formula: A = W * L

Replace the variables:

24 = (2L - 8) * L

24 = 2 $L^{2}$ - 8L

0 = 2 $L^{2}$ - 8L - 24

2 $L^{2}$ - 8L - 24 = 0

Solve; if you don't know how to solve it using this method, let me know. It's the expression $Ax^{2} +Bx+C$

1. $2 (\frac{(2L^2 - 8L - 24)}{2})$

2. $\frac{(2L)^2 - 8(2L) - 48}{2}$

3. $\frac{(2L - 12)(2L + 4)}{2}$

4. $2(\frac{(L - 6)(2L + 4)}{2})$

5. (L-6) (2L+4)

6. L-6 = 0 AND 2L+4 = 0

L - 6 =0

L = 6

---------------------------------

2L = -4

L = $\frac{-4}{2}$

L = -2

Since the length cannot be negative, the only real value is 6.

Area: 24 $m^{2}$

Width: 2L - 8 m

Length: 6 m

Calculate width:

W = 2L - 8

W = 2(6) - 8

W = 12 - 8

W = 4 m

3 0

3 years ago

Baseballs and softballs com in different sizes for different leagues. If the diameter of a baseball is 3 inches and a softball i

Vanyuwa [196]

Answer:

Step-by-step explanation:

Alright, lets get started.

Diameter of baseball is given as 3 inches.

Hence the radius of baseball will be : $\frac{3}{2}=1.5$

Hence the volume of baseball is : $\frac{4}{3}\pir^3$

Hence the volume of baseball is : $\frac{4}{3}\pi1.5^3$

Hence the volume of baseball is : 14.13 inches cube

Now, diameter of softball is given as 3.8 inches.

Hence the radius of softball will be : $\frac{3.8}{2}=1.9$

Hence the volume of baseball is : $\frac{4}{3}\pir^3$

Hence the volume of baseball is : $\frac{4}{3}\pi1.9^3$

Hence the volume of baseball is : 28.72 inches cube

Hence the difference of volumes will be: $28.72-14.13$

Hence the difference of volumes will be 14.59 or 14.6 inches cube

So the answer is 14.6 inches cube. : Answer

Hope it will help :)

7 0

3 years ago

Read 2 more answers