Solve for the value of c (2c-4) (5c+3)

5⁸<br>– = 5ⁿ<br>5⁴<br><br>work out the value of n.

Hitman42 [59]

Answer:

5 power 2 is the answer

Step-by-step explanation:

7 0

3 years ago

What is the surface area of the rectangular prism shown above?

Mariulka [41]

Answer:

A=248

Step-by-step explanation:

l=10

w=4

h=6

7 0

4 years ago

Margaret has 16 yards of fabric and she is making dresses for z doll write the expression for the length of fabric used for each

emmasim [6.3K]

<h3>The expression for the length of fabric used for each doll is $\frac{16}{z}\ yards$ </h3>

<em><u>Solution:</u></em>

Given that,

Margaret has 16 yards of fabric

she is making dresses for z doll

Therefore,

Total length of fabric = 16 yards

Number of dresses = z dolls

Therefore,

$\text{ length of fabric used for each doll } = \frac{ \text{ Total length of fabric }} {\text{ z dolls }}\\\\\text{ length of fabric used for each doll } = \frac{16}{z}\ yards$

Thus, the expression for the length of fabric used for each doll is $\frac{16}{z}\ yards$

7 0

4 years ago

How many 16-ounce bottles would be needed to hold the same total amount of water 56 bottles that each holds 20 ounces

snow_lady [41]

70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.

Step-by-step explanation:

Given,

56 bottles hold 20 ounces each.

Total amount 56 bottles hold= 56x20

Total amount hold by 56 bottles= 1120 ounces

Let the number of 16 ounces bottles be = x

Total amount hold by x bottles = 16x

According to the given statement both amounts are same;

$16x=1120\\Dividing\ both\ sides\ by\ 16\\\frac{16x}{16} = \frac{1120}{16} \\x=70$

70 bottles will hold 16 ounces amount same as 56 bottles hold 20 ounces.

Keywords: Division, Multiplication

Learn more about division at:

#LearnwithBrainly

6 0

3 years ago

Solve the following system of linear equations: 3x1+6x2+6x3 = -9 -2x1–3x2-3x3 = 3 If the system has infinitely many solutions, y

choli [55]

Answer:

The set of solutions is $\{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number} \}$

Step-by-step explanation:

The augmented matrix of the system is $\left[\begin{array}{ccccc}3&6&6&-9\\-2&-3&-3&3\end{array}\right]$ .

We will use rows operations for find the echelon form of the matrix.

In row 2 we subtract $\frac{2}{3}$ from row 1. (R2- 2/3R1) and we obtain the matrix $\left[\begin{array}{cccc}3&6&6&-9\\0&1&1&-7\end{array}\right]$
We multiply the row 1 by $\frac{1}{3}$ .

Now we solve for the unknown variables:

$x_2+x_3=-7$ , $x_2=-7-x_3$
$x_1+2x_2+2x_3=-2$ , $x_1+2(-7-x_3)+2x_3=-2$ then $x_1=12$

The system has a free variable, the the system has infinite solutions and the set of solutions is $\{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number} \}$

6 0

3 years ago