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Y_Kistochka [10]
3 years ago
15

Find the quotient. 3/8 divided by 8

Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer: 3/64

Step-by-step explanation:

Dividing by 8 is the same thing as multiplying by the reciprocal (just flip the fraction). Since 8/1 is the same things as 8, here, the reciprocal is 1/8. So just multiply 3/8 by 1/8. You should get 3/64. Hope this helps!

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Please Need Help. Thank You :)<br><br><br>Please find the Volume of these cylinders:
vladimir2022 [97]

Answer:

the one for the finding the height is 3.3, the one with 7 as the height is 351.86, and the one with 3 as the height is 150.8

Step-by-step explanation:

h=V

πr2=41.5

π·22≈3.30247

V=πr2h=π·42·7≈351.85838

V=πr2h=π·42·3≈150.79645

4 0
3 years ago
Please help this is due Friday at 11:59 and i don't get it . please answer it step by step ​
Tresset [83]

Answer:

The angle <SXN measures 108 degrees, and the angle <SXV measures 72 degrees.

Step-by-step explanation:

To determined the angles <SXN and <SXV, you need to first figure out what <SNX amounts to and then use the angle-sum property of the triangle NSX.

The following is true:

<SNX = 90 - <QNX    (this is because <QNS is a right angle)

and

<QNX = <YNP = 56     (given)

so

<SNX = 90 - 56 = 34 degrees

Now, using the triangle-sum property:

<SXN = 180 - <SNX - <XSN = 180 - 34 - 38 = 108 degrees

Now that you have <SXN, to determine <SXV use the property that <SXV is supplementary angle to <SXN, hence

<SXV = 180 - <SXN = 180 - 108 = 72 degrees

All done!


5 0
4 years ago
Let Z = 5 + 12i, The value of |Z| is
gtnhenbr [62]

Answer: 13

Step-by-step explanation:

/ 5 + 12i/ = \sqrt{(5 + 12i)(5 + 12i)}

= \sqrt{25 + 144}

=\sqrt{169}

= 13

3 0
3 years ago
Find the area of the following regions, expressing your results in terms of the positive integer n ≥ 2. The region bounded by
cluponka [151]

Answer:

The area of the searched region is A= a+b+ \frac{2n}{n+1}- \frac{n(a^{\frac{n+1}{n} }+b^{\frac{n+1}{n} }) }{n+1}-2

Step-by-step explanation:

If you want to find the area of a region bounded by functions f(x) and G(x) between two limits (a,b), you have to do a double integral. you must first know which of the functions is greater than the other for the entire domain.

In this case, for 0<x<1, f(x)<g(x)

while for 1<x, g(x)<f(x).

Therefore if our domain is all real numbers superior to 0 (where the limit 0<a<1 and 1<b), we have to do 2 integrals:

A=A(a<x<1)+A(1<x<b)

A(a

A(1

A=a-1 +\frac{n}{n+1} - \frac{na^{\frac{n+1}{n} } }{n+1} +  b-1 + \frac{n}{n+1} - \frac{nb^{\frac{n+1}{n} } }{n+1} = a+b+ \frac{2n}{n+1}  - \frac{n(a^{\frac{n+1}{n} }+b^{\frac{n+1}{n} }) }{n+1}   -2

3 0
3 years ago
2. Solve for b in the linear equation<br> 6b - 24 = 3(5b - 2)
Step2247 [10]

Answer: b = −2

Step-by-step explanation:

6 0
4 years ago
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