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marin [14]
3 years ago
15

A van travels 150 miles on 6 gallons of gas. How many gallons will it need to travel 325 miles?

Mathematics
1 answer:
diamong [38]3 years ago
8 0

Answer:

C. 13 gallons

Step-by-step explanation:

150 divided by 6 is 25. 325 divided by 25 is 13.

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Enter the terms and the coefficients of the expression.
levacccp [35]

Answer:the terms are 4x,50y, and 40 the coefficients are 4 and 50

Step-by-step explanatio

7 0
3 years ago
A system has a continuous load requirement of 80 MW. Find the expected load loss and the probability of load loss (loss of load
MariettaO [177]

Answer:

Expected load loss = 1.35

P (Load Loss) = 0.127

Step-by-step explanation:

The probability of failure is: <em>q</em> = 0.015

The probability of success is: <em>p</em> = 1 - <em>q</em> = 1 - 0.015 = 0.985

The number of units the generation system is composed of is, <em>n</em> = 9.

The capacity of each unit is 10 MW.

Let <em>X</em> = number of units that failed or are unavailable.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>q.</em>

The probability function is:

P (X=x)={n\choose x}p^{x}(1-p)^{n-x}; <em>x</em> =0, 1, 2, 3...

  • The expected number of failures is:

E(X)=nq=9\times0.015=0.135

Then the expected load loss is:

E (Load\ Loss)=10\times E(X)=10\times 0.135=1.35

Thus, the expected load loss is 1.35.

  • The load loss will be when at least one unit fails.

The probability that at least one unit fails is:

P (X ≥ 1) = 1 - P (X < 1) = 1 - P (X = 0)

             =1-[{9\choose 0}(0.015)^{0}(1-0.015)^{9-0}]\\=1-0.8728\\=0.12718\\\approx0.127

Thus, the probability of load loss is 0.127.

5 0
3 years ago
Aisha can walk 9 miles in 2 hours. At this rate, how many miles will she walk during the week if she walks a total of 6 hours?
Nikolay [14]

Answer: Aisha can walk 27 miles during the week if she walks a total of 6 hours.

Step-by-step explanation:

9/2=4.5

4.5*6=27

3 0
3 years ago
Read 2 more answers
Which shows the dimensions of two rectangular prisms that have volumes of 72 cm3 but different surface areas? A. 6 cm by 3 cm by
Nookie1986 [14]
To solve, lets find the volumes of all of the options...

V=l*w*h

A. 
6*3*4=72cm³
12*2*3=72cm³

B.
2*4*9=72cm³
9*4*2=72cm³

C.
3*3*8=72cm³
2*6*8=96cm³

D.
6*3*4=72cm³
9*4*3=108cm³

We can conclude that C & D aren't the answer, since they contain prisms that don't have a volume of 72cm³.

Now lets solve for the surface area of A and B...

A. 
sA=2(wh+lw+lh)=2(6*3+4*6+4*3)=2(18+24+12)=2(54)=108cm²
sA=2(wh+lw+lh)=2(12*2+3*12+3*2)=2(24+36+6)=2(56)=112cm²


B.
sA=2(wh+lw+lh)=2(2*4+9*2+9*4)=2(8+18+36)=2(62)=124cm²
sA=2(wh+lw+lh)=2(9*4+2*9+2*4)=2(36+18+8)=2(62)=124cm²

A is the only option with both similar volumes of 72cm³ and different surface areas...

Answer=A
3 0
3 years ago
Read 2 more answers
Simplify as a ratio: 100:199:47
rodikova [14]

Answer:

Find GCF of all values in the given ratio

GCF(100, 199, 47) = 1

When GCF value is equal to 1, the given ratio can not be simplified.

Step-by-step explanation:

It cant be simplified

3 0
3 years ago
Read 2 more answers
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