The more reasonable measurement of the distance between the tracks on a CD is 1.6 ⋅ 10^-3 mm. This is also equal to 0.0016mm. <span>1.6 ⋅ 10^3 mm is too large for a CD track</span>
Answer:
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Step-by-step explanation:
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Answer: 1440
Explanation: when you split it into two shapes (I split it where the split is splitting the eight up) you find the volume of them both. Top shape= 4x4x10=80 bottom shape= 8x8x10=640.
640+80= 720
You will then need to multiply by two (or add 720+720) to get the answer 1440
Answer:
Should be 620,000
Step-by-step explanation:
Given that,
KM bisects ∠LKJ.
m∠LKM = 4x + 12 and m∠MKJ = 6x - 6
To find,
The value of x.
Solution,
As KM bisects ∠LKJ. It would mean that,
m∠LKM = m∠MKJ
Putting the above values,
4x+12=6x-6
We can solve the above equations as follows :
4x-6x=-12-6
-2x=-18
x=9
Therefore, the value of x is equal to 9.