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3 years ago

This is a trignometry questionhope u will do for me i will mark brainliest..:)

Mathematics

1 answer:

Anastasy [175]3 years ago

5 0

Step-by-step explanation:

$\cos^{4} x - \sin^{4} x$

$= ( \cos^{2} x + \sin^{2} x)( \cos^{2} x - \sin^{2} x)$

$= (1 - \sin^{2} x + \sin^{2} x)( 1 - \sin^{2} x - \sin^{2} x)$

$= 1 - 2\sin^{2} x$

Note: I replaced all cos^2x terms using the identity

$\cos^{2} x = 1 - \sin^{2} x$

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Does anybody know what 8(11-3) -2(4+1) is

lina2011 [118]

Its 58................

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3 years ago

Read 2 more answers

An airplane descends 1.5 miles to an elevation of 5.25 miles. Write and solve an equation to find the elevation of the plane bef

DerKrebs [107]

2.25 is the elevation of the plane before its decent

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3 years ago

0/1

pychu [463]

Answer:

68.8 sq. inches.

Step-by-step explanation:

The triangular surfaces have sides 2 in by 3 in by 4 in.

So, half perimeter, s = $\frac{2 + 3 + 4}{2} = 4.5$

So, the area of the triangular face is $\sqrt{s(s - 4)(s - 2)(s - 3)} = \sqrt{4.5 \times 0.5 \times 2.5 \times 1.5} = 2.9$ sq. inches.

Now, the total surface area of the right triangular prism will be (2.9 × 2) + 7(2 + 3 + 4) = 68.8 sq. inches. (Answer)

4 0

2 years ago

If the total number of books checked out of the library at your high school is 14,400 and the student population is about 2400.

Whitepunk [10]

The number of books taken by each student is 6.

<h3>What is an average?</h3>

Average is defined as the ratio of the sum of the number of the data sets to the total number of the data. The average actually determines the middle value of the data.

Given that the total number of books checked out of the library at your high school is 14,400 and the student population is about 2400.

The average is calculated by dividing the sum of the total number of items by the total counts of the items.

Average = 14400 / 2400

Average = 6

Therefore, the number of books taken by each student is 6.

To know more about an average follow

brainly.com/question/20118982

#SPJ2

5 0

1 year ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Anettt [7]

Answer:

Choice C: approximately 121 green beans will be 13 centimeters or shorter.

Step-by-step explanation:

What's the probability that a green bean from this sale is shorter than 13 centimeters?

Let the length of a green bean be $X$ centimeters.

$X$ follows a normal distribution with

mean $\mu = 11.2$ and
standard deviation $\sigma = 2.1$ .

In other words,

$X\sim \text{N}(11.2, 2.1^{2})$ ,

and the probability in question is $X \le 13$ .

Z-score table approach:

Find the z-score of this measurement:

$\displaystyle z= \frac{x-\mu}{\sigma} = \frac{13-11.2}{2.1} = 0.857143$ . Closest to 0.86.

Look up the z-score in a table. Keep in mind that entries on a typical z-score table gives the probability of the left tail, which is the chance that $Z$ will be less than or equal to the z-score in question. (In case the question is asking for the probability that $Z$ is greater than the z-score, subtract the value from table from 1.)

$P(X\le 13) = P(Z \le 0.857143) \approx 0.8051$ .

"Technology" Approach

Depending on the manufacturer, the steps generally include:

Locate the cumulative probability function (cdf) for normal distributions.
Enter the lower and upper bound. The lower bound shall be a very negative number such as $-10^{9}$ . For the upper bound, enter $13$
Enter the mean and standard deviation (or variance if required).
Evaluate.

For example, on a Texas Instruments TI-84, evaluating $\text{normalcdf})(-1\text{E}99,\;13,\;11.2,\;2.1 )$ gives $0.804317$ .

As a result,

$P(X\le 13) = 0.804317$ .

Number of green beans that are shorter than 13 centimeters:

Assume that the length of green beans for sale are independent of each other. The probability that each green bean is shorter than 13 centimeters is constant. As a result, the number of green beans out of 150 that are shorter than 13 centimeters follow a binomial distribution.

Number of trials $n$ : 150.
Probability of success $p$ : 0.804317.

Let $Y$ be the number of green beans out of this 150 that are shorter than 13 centimeters. $Y\sim\text{B}(150,0.804317)$ .

The expected value of a binomial random variable is the product of the number of trials and the probability of success on each trial. In other words,

$E(Y) = n\cdot p = 150 \times 0.804317 = 120.648\approx 121$

The expected number of green beans out of this 150 that are shorter than 13 centimeters will thus be approximately 121.

7 0

3 years ago

This is a trignometry questionhope u will do for me i will mark brainliest..:)​

This is a trignometry questionhope u will do for me i will mark brainliest..:)