Answer:
No DB is not a perpendicular bisector of AC
Step-by-step explanation:
This is because as AC is a straight line it's angle degree is 180 which when bisected by DB becomes,
180 ÷ 2 = 90
On both the angles i.e <BDC = <NDA = 90°
To make it a perpendicular bisector but
<BDC is not equal to <NDA is not equal to 90°.
Hence, DB is not a perpendicular bisector of line AC.
Answer:
40
Step-by-step explanation:
f(4) = 3(4²) - 2(4)
= 3(16) - 8
= 48 - 8
= 40
when x=4, f(x) = 40
Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2
Area of semicircle:
A = 1/2 π r^2 = 1/2 π 6^2 = 18<span>π m^2
Area of figure = </span>Area of semicircle + Area of Triangle
Area of figure = 18π + 30 m^2
Answer is C.
18π + 30 m^2
Answer:
-127
Step-by-step explanation:
