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3 years ago

Please help quick!!!!!!

Mathematics

1 answer:

bekas [8.4K]3 years ago

3 0

Answer:

I think its C

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What is the total amount of current liabilities to be reported on xyz company's 12/31/x1 classified balance sheet? $22,600 $74,3

Lelechka [254]

Based on the financial details given, the total amount of current liabilities on xyz company's 12/31/x1 classified balance sheet is $22,600.

<h3>What are the total current liabilities?</h3>

The current liabilities can be found by the formula:

= Accounts Payable + Salaries Payable + Interest Payable + Utilities Payable

As the above are all the current liabilities to XYZ company, the current liabilities are:

= 11,300 + 2,500 + 1,900 + 6,900

= $22,600

Find out more on balance sheets at brainly.com/question/1113933

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1 year ago

A coffee shop collected the following information regarding purchases from 110 of its customers 59 purchased coffee 39 purchased

Andrej [43]

Answer:

Let X be the number of customer purchased coffee

Let Y be the number of customer purchased donuts

Then $X\cap Y$ is the number of customer purchased both coffee and donuts

$X\cup Y$ is the number of customer purchased both coffee or donuts

The Number of customers purchased only Coffee:

Number of customers purchased only donuts =n(X -Y)

$n( X -Y) = n(X) - n(X \cap Y)$

n(X-Y) = 59 -16

n(Y - X) = 43

The Number of customers purchased only donuts:

Number of customers purchased only donuts =n(Y -X)

$n(Y - X) = n(Y) - n(X \cap Y)$

n(Y - X) = 39 -16

n(Y - X) = 23

The Number of customers did not purchase either of these items:

Number of customers did not purchase either of these items = $n(X\cup Y)^{\prime}$

First lets find $n(X\cup Y)$

$n(X\cup Y) = n(X) + n(Y) - n( X \cap Y)$

$n(X\cup Y) = 59 + 39 - 16$

$n(X\cup Y) = 82$

$n(X\cup Y)^{\prime}$ = $110 - n(X\cup Y)$ = 28

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4 years ago

Blank thousands equals 5,000 ones?

KIM [24]

I'm pretty positive that the answer is 500. just use your powers of 10 and you'll find it easy. don't think about it too hard! i really hope that helps!!! :)

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Mice21 [21]

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Step-by-step explanation:

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