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Maslowich
2 years ago
10

In the figure below, PEZS. What is the value of x? P 7x+4 6x+8 T 5x+10 S

Mathematics
1 answer:
mr_godi [17]2 years ago
7 0
The answer is P=S23 because you add them all Isaac nut on didn’t get apples
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What is 6^7 in expanded form?​
Wewaii [24]

Answer:

6x6x6x6x6x6x6

Step-by-step explanation:

6^2 is 6x6

6^3 is 6x6x6

etc...

6^7 is 6x6x6x6x6x6x6

8 0
3 years ago
Read 2 more answers
The students at a High School earned money for an international animal rescue foundation. 82 seniors earned an average $26.75 pe
Anon25 [30]

Answer: A. $16.13

Step-by-step explanation:

Total students = 82+74+96+99 =351

Sum of earnings of 82 seniors  = $26.75  x 82= $2193.5

Sum of earnings of 74 juniors  = $12.25 x 74 = $906.5

Sum of earnings of 96 sophomores  = $15.50  x 96 = $1488

Sum of earnings of 99 freshmen  =  $10.85 x 99 = $1074.15

Total earnings =  $2193.5  + $906.5+  $1488 +$1074.15

= $5662.15

(Total earnings) ÷ (Total students )

= $5662.15÷ 351

= $16.13

4 0
3 years ago
Find two number nearest to 8888888 which are exactly divisible by 2915​
Marysya12 [62]

Step-by-step explanation:

Given problem is to find nearest number,

= 8888888/2915

quotient = 3049

remainder= 1053

Now, 2915-1053 = 1862

8888888+1862 = 8890750

8888888-1053 = 8887835

Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750

3 0
2 years ago
Please answer the following questions​
laila [671]

Answer:

4a) 110 square centimetres

4b) 127 square centimetres

6) 292 square centimetres

8) 800 tiles

Step-by-step explanation:

4. We need to find the area of the large rectangle and then deduct the area of the unshaded part:

a) The large rectangle has dimensions 12 cm by 15 cm. Its area is:

A = 12 * 15 = 180 square centimetres

The unshaded part has a length of 15 - (3 + 2) cm i.e. 10 cm and a width of 7 cm. Its area is:

a = 10 * 7 = 70 square centimetres

Therefore, the area of the shaded part is:

A - a = 180  - 70 = 110 square centimetres

b) The large rectangle has dimensions 13 cm by 11 cm. Its area is:

A = 13 * 11 = 143 square centimetres

The unshaded part has dimensions 8 cm by 2 cm. Its area is:

a = 8 * 2 = 16 square centimetres

Therefore, the area of the shaded part is:

A - a = 143 - 16 = 127 square centimetres

6. The background area of the space not covered by the photograph is the area of the frame minus the area of the photograph.

The frame has dimensions 24 cm by 18 cm. Therefore, its area is:

A = 24 * 18 = 432 square centimetres

The photograph has dimensions 14 cm by 10 cm. Therefore, its area is:

a = 14 * 10 = 140 square centimetres

Therefore, the background area of the space not covered by the photograph is:

A - a = 432 - 140 = 292 square centimetres

8) The floor has dimensions 8 m by 4 m. The area of the floor is:

A = 8 * 4 = 32 square centimetres

Each square tile has dimensions 20 cm by 20 cm. In metres, that is 0.2 m by 0.2 m. The area of each tile is:

a = 0.2 * 0.2 = 0.04 square metres

The number of tiles that are needed is the area of the floor divided by the area of each tile:

A / a = 32 / 0.04 = 800 tiles

4 0
3 years ago
*PLEASE HELP URGENT NEED TO TURN IN TOMORROW* WILL GIVE BRAINY AND 60 OR MORE POINTS
pogonyaev

Answer:

2.  92 ounces of Sprite

3.  1/6 do not want mustard on their ham sandwiches

4.  6 hours playing volleyball

5. 32 portions

Step-by-step explanation:

2.  Sam has 8 cans of Sprite.  Each can is 11 2/4 ounces

We can simplify 2/4 to 1/2

Multiply the number of cans by  the ounces per can

8 * 11  1/2

8 * 11.5

92 ounces

3.  1/2 of the students want ham.  1/3 of those do not want mustard

We multiply 1/2*1/3 = 1/6

1/6 of the students do not want mustard on their ham sandwiches

4.  8 hours at the beach.  3/4 of the time was spent playing volleyball

Multiply this together

8*3/4 = 8/4*3 = 2*3 = 6 hours

5.  We have 4 lbs of wings.  We divide it into 1/8 lbs parts

4 ÷ 1/8

Copy dot flip

4 * 8/1

32 portions

8 0
3 years ago
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