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saveliy_v [14]
2 years ago
9

Find the 91st term of the arithmetic sequence 4, 6, 8,

Mathematics
2 answers:
olga_2 [115]2 years ago
8 0

Answer:

  • 91st term of the arithmetic sequence 4, 6, 8... is 184.

Step-by-step explanation:

  • Comman difference = 8 - 6 = 2
  • a = 4
  • n = 91

\longrightarrow \: \: a _{n } =a (n - 1)d

\longrightarrow \: \: a_{91} = 4(91 - 1) \times 2

\longrightarrow \: \: a _{91}= 4 +(90) \times 2

\longrightarrow \: \: a _{60}= 4 + 180

\longrightarrow \: \: a_{60}= 184

\therefore 91st term of the arithmetic sequence 4, 6, 8.. is 184

Jet001 [13]2 years ago
5 0

Answer:

184

Step-by-step explanation:

Find the common difference first   d = 6 - 4 = 2

first term  a_1  = 4

a_n = (n -1)*d + a_1

a_91 = (91 - 1) * 2 + 4

a_91  is the 91st term:

a_91 = 90*2 + 4

a_91 = 180 + 4 = 184

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