Question

Find the 91st term of the arithmetic sequence 4, 6, 8,

Answer 1

Answer:

• 91st term of the arithmetic sequence 4, 6, 8... is 184.

Step-by-step explanation:

• Comman difference = 8 - 6 = 2
• a = 4
• n = 91

$\longrightarrow \: \: a _{n } =a (n - 1)d$

$\longrightarrow \: \: a_{91} = 4(91 - 1) \times 2$

$\longrightarrow \: \: a _{91}= 4 +(90) \times 2$

$\longrightarrow \: \: a _{60}= 4 + 180$

$\longrightarrow \: \: a_{60}= 184$

$\therefore$ 91st term of the arithmetic sequence 4, 6, 8.. is 184

Answer 2

Answer:

184

Step-by-step explanation:

Find the common difference first   d = 6 - 4 = 2

first term  a_1  = 4

a_n = (n -1)*d + a_1

a_91 = (91 - 1) * 2 + 4

a_91  is the 91st term:

a_91 = 90*2 + 4

a_91 = 180 + 4 = 184