Need help please! very short!
2 answers:
13. You can use a calculator to compute the constants for an exponential fit to the data. Mine says the best fit is
A. y = 3*1.1^x
You can also write the equation directly from any two of the data points. I like to choose ones that have integer values for x. From two points (x1, y1) and (x2, y2) you can write the exponential function as ...
.. y = y1*(y2/y1)^((x -x1)/(x2-x1))
.. y = 3.63*(4.39/3.63)^((x -2)/2) . . . . . . . . . . . . . . . fill in the data
.. y = (3.63*(4.39/3.63^-1))*((4.39/3.63)^(1/2))^x . . rearrange to a*b^x form
.. y = 3.00*1.10^x
14. Selection G is the only one that represents exponential growth.
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F & H are linear functions; J is exponential decay (the base is less than 1).
A. y = 3*1.1^x
You can also write the equation directly from any two of the data points. I like to choose ones that have integer values for x. From two points (x1, y1) and (x2, y2) you can write the exponential function as ...
.. y = y1*(y2/y1)^((x -x1)/(x2-x1))
.. y = 3.63*(4.39/3.63)^((x -2)/2) . . . . . . . . . . . . . . . fill in the data
.. y = (3.63*(4.39/3.63^-1))*((4.39/3.63)^(1/2))^x . . rearrange to a*b^x form
.. y = 3.00*1.10^x
14. Selection G is the only one that represents exponential growth.
___
F & H are linear functions; J is exponential decay (the base is less than 1).
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Answer:
You can write this as (-infinity, 7) if you aren't able to use the infinity symbol.
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Explanation:
Think of x < 7 as writing
So x is between negative infinity and 7, excluding both endpoints.
To write in interval notation, we write
The curved parenthesis tell us to exclude the endpoint.