Answer:
x=41
Step-by-step explanation:
x is your hypotenuse , and cuz its a right triangle you can use pythogorean theorem so +
=
, and c is the same as "x"
once u simplify that u end up with c=41 or in your case x=41 :)
Need help please! very short!
2 answers:
13. You can use a calculator to compute the constants for an exponential fit to the data. Mine says the best fit is
A. y = 3*1.1^x
You can also write the equation directly from any two of the data points. I like to choose ones that have integer values for x. From two points (x1, y1) and (x2, y2) you can write the exponential function as ...
.. y = y1*(y2/y1)^((x -x1)/(x2-x1))
.. y = 3.63*(4.39/3.63)^((x -2)/2) . . . . . . . . . . . . . . . fill in the data
.. y = (3.63*(4.39/3.63^-1))*((4.39/3.63)^(1/2))^x . . rearrange to a*b^x form
.. y = 3.00*1.10^x
14. Selection G is the only one that represents exponential growth.
___
F & H are linear functions; J is exponential decay (the base is less than 1).
A. y = 3*1.1^x
You can also write the equation directly from any two of the data points. I like to choose ones that have integer values for x. From two points (x1, y1) and (x2, y2) you can write the exponential function as ...
.. y = y1*(y2/y1)^((x -x1)/(x2-x1))
.. y = 3.63*(4.39/3.63)^((x -2)/2) . . . . . . . . . . . . . . . fill in the data
.. y = (3.63*(4.39/3.63^-1))*((4.39/3.63)^(1/2))^x . . rearrange to a*b^x form
.. y = 3.00*1.10^x
14. Selection G is the only one that represents exponential growth.
___
F & H are linear functions; J is exponential decay (the base is less than 1).
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