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Nutka1998 [239]
3 years ago
10

Okay i have to do a whole test and i need help!! The picture is up there!

Mathematics
2 answers:
Natalka [10]3 years ago
5 0

Answer:

a is triangular prism :)

dedylja [7]3 years ago
4 0

Answer:

Before you take a proctored exam, make sure have approved ID verification photos ... Photo verification may take up to 5 days to process, so please make sure to ... approval above, you would also need to complete onboarding exam 5 days

Step-by-step explanation:

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The ______ of a radical expression is the number indicating which root (square root, cube root, etc.) is meant.
Kobotan [32]
The correct answer is index

8 0
3 years ago
Read 2 more answers
What is the volume of the right prism 8 mm 18 mm 12 mm
lisabon 2012 [21]
It will be clearly  B.38mm3
7 0
3 years ago
Darren is painting a wooden block as part of his art project The block is a rectangular prism that is 12cm long by 9 cm wide by
Ksenya-84 [330]

Answer:

<h3>The surface area in square meters that Darren has to paint is 426cm^2</h3><h3>∴ A=426cm^2</h3>

Step-by-step explanation:

Given that Darren is painting a wooden block is a rectangular prism

Its length is 12 cm ,width is 9 cm and height is 5 cm

<h3>To find the surface area in square meters that Darren has to paint :</h3>

Let l be the length, w be the width and h be the height

Then l=12 cm , w=9 cm and h=5 cm

The formula for the Surface area is

A=2(lw+wh+hl) square units

Substitute the values in formula we get,

A=2(12(9)+9(5)+5(12))

=2(108+45+60)

=2(213)

=426

<h3>∴ A=426cm^2</h3><h3>∴ the surface area in square meters that Darren has to paint is 426cm^2</h3>

5 0
3 years ago
Which expression is it equivalent to?
horrorfan [7]
Option A) Is the answer. \boxed{\mathbf{\dfrac{3f^3}{g^2}}}

For this question; You are needed to expose yourselves to popular usages of radical rules. In this we distribute the squares as one-and-a-half fractions as the squares eliminate the square roots. So, as per the use of fraction conversion from roots. It becomes relatively easy to solve and finish the whole process more quicker than everyone else. More easier to remember.

Starting this with the equation editor interpreter for mathematical expressions, LaTeX. Use of different radical rules will be mentioned in between the steps.

Radical equation provided in this query.

\mathbf{\sqrt{\dfrac{900f^6}{100g^4}}}

Divide the numbered values of 900 and 100 by cancelling the zeroes to get "9" as the final product in the next step.

\mathbf{\sqrt{\dfrac{9f^6}{g^4}}}

Imply and demonstrate the rule of radicals. In this context we will use the radical rule for fractions in which a fraction with a denominator of variable "a" representing a number or a variable, and the denominator of variable "b" representing a number or a variable are square rooted by a value of "n" where it can be a number, variable, etc. Here, the radical of "n" is distributed into the denominator as well as the numerator. Presuming the value of variable "a" and "b" to be greater than or equal to the value of zero. So, by mathematical expression it becomes:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{\dfrac{a}{b}} = \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}, \: \: a \geq 0 \: \: \: b \geq 0}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{\sqrt{g^4}}}

Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{g^4} = g^{\frac{4}{2}}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{g^2}}

Exhibit the radical rule for two given variables in this current step to separate the variable values into two new squares of variables "a" and "b" with a radical value of "n". Variables "a" and "b" being greater than or equal to zero.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}, \: \: a \geq 0 \: \: \: b \geq 0}}

So, the square roots are separated into root of 9 and a root of variable of "f" raised to the value of "6".

\mathbf{\therefore \quad \dfrac{\sqrt{9} \sqrt{f^6}}{g^2}}

Just factor out the value of "3" as 3 × 3 and join them to a raised exponent as they are having are similar Base of "3", hence, powered to a value of "2".

\mathbf{\therefore \quad \dfrac{\sqrt{3^2} \sqrt{f^6}}{g^2}}

The radical value of square root is similar to that of the exponent variable term inside the rooted enclosement. That is, similar exponential values. We apply the following radical rule for these cases for a radical value of variable "n" and an exponential value of "n" with a variable that is powered to it.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^n} = a^{\frac{n}{n}} = a}}

\mathbf{\therefore \quad \dfrac{3 \sqrt{f^6}}{g^2}}

Again, Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{f^6} = f^{\frac{6}{2}} = f^3}

\boxed{\mathbf{\underline{\therefore \quad Required \: \: Answer: \dfrac{3f^3}{g^2}}}}

Hope it helps.
8 0
3 years ago
Which of the following is a solution of x2 + 2x + 8?
zubka84 [21]
Using the quadratic equation we get:
\frac{ - 2 + - \sqrt{4 - 32} }{2} = \frac{ - 2 + - \sqrt{ - 28} }{2}

Factoring out 2 we get
\frac{ - 2 + - 2\sqrt{ - 7} }{2} = - 1( + - ) \sqrt{ - 7}
Factoring out the imaginary number:
- 1 + \sqrt{7} i \: (and) \: - 1 - \sqrt{7} i
So b.
4 0
3 years ago
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