Answer: A low pCO2 indicates respiratory alkalosis which may be primary or secondary to a primary metabolic acidosis. Bicarbonate is calculated from measured [H+] and pCO2 values. A high standard [HCO3- ] indicates either primary metabolic alkalosis or a compensatory response to a primary respiratory acidosis.
Explanation: an increase in PCO2 causes a decrease in pH, which will increase minute ventilation and therefore increase alveolar ventilation to attempt to reach homeostasis. The higher the minute ventilation, the more exchange and loss of PCO2 will occur inversely.
Answer:
Option (c).
Explanation:
Eukaryotes may be defined as the organism that contains the well defined nucleus and membrane bound cell organelle. The eukaryotes contains morte cell organelles as compared with prokaryotes.
The ribosomes of eukaryotes are larger than the ribosomes of prokaryotes. The 80'S ribosomes are present in eukaryotes whereas 70'S ribosomes are present in prokaryotes.
Thus, the correct answer is option (c).
Answer:
The results of the experiment is a process called competitive inhibition.
Explanation:
Competitive inhibition is a process where an inhibitor (RGD tripeptides in this case) that resembles a normal substrate bind the active site of an enzyme and prevents the a real substrate from binding and a product from being formed (blocking enzymes active site).
When RDG tripeptides are added the cells would not adhere to the dish (competitive inhibition).
Answer:
We arent gonna talk about your username...
Explanation:
possessing characters of both sexes and especially both male and female reproductive structures
hope this helps.
