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azamat
3 years ago
7

Kira purchased n notebooks. They were 4 dollars each. Write an equation to represent the total cost c that Kira paid.

Mathematics
2 answers:
Anna [14]3 years ago
8 0
I believe C=4n is the answer
Verdich [7]3 years ago
7 0
4n=c because if you new how many books Kira bought you would multiply that by the cost of one notebook, $4*notebook(s), which would then equal the cost.
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If y varies directly as x and z, and y=8/3 when x=1 and z=4, find y when x=6 and z=3
Butoxors [25]

8/3 =k(1)(4)

8/3 =4k

k=(8/3)/4

k =2/3


y= 2/3 *(6)(3)

y = 2/3 x 18

y = 12


7 0
3 years ago
Emily and a friend bought two tickets to see a soccer game. Each ticket cost $8.25. The friends paid a total of $24.50, which in
solniwko [45]
2\cdot8.25=16.5\\\\24.5-16.5=8\\\\8:2=4\\\\\frac{4}{8.25}\cdot100\%=\\\\\frac{400}{8.25}\%=\\\\48.48\%
6 0
4 years ago
What's p-(8+m) over -1+p if m is 1 1/9 and p is 1 7/8 please help
djyliett [7]
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that's as far as it can be solved
8 0
3 years ago
Select the statements that are true for the graph of y=(x+2)2+4 .
guapka [62]
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8 0
3 years ago
Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu
valina [46]

Answer:

Step-by-step explanation:

Given that Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the numerous types of solder defects (e.g., pad non-wetting, knee visibility, voids) and even the degree to which a joint possesses one or more of these defects.

Let A- event inspect A found defective , B - inspector B found defective

P(A) = 0.0744\\P(B) =0.00760

P(AUB) = 0.0880,  

a) Probability that the selected joint was judged to be defective by neither of the two inspectors=P((AUB)')=1-0.0880=0.9120

b) Probability that the selected joint was judged to be defective by inspector B but not by inspector A

=P(AB')\\=P(A)-P(AB)\\

P(AB) = P(A)+P(B)-P(AB)\\= 0.0744+0.0760-0.0880\\=0.0624

Hence

P(AB')\\=P(A)-P(AB)

= 0.0766-0.0624

=0.0142

7 0
4 years ago
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