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hram777 [196]
3 years ago
13

1÷-½ aswer please!!​

Mathematics
2 answers:
Leviafan [203]3 years ago
8 0
The answer to this is -2
adell [148]3 years ago
3 0

Answer:

( - 2)

Step-by-step explanation:

1 \div  -  \frac{1}{2}  \\ 1 \times   - \frac{2}{1}  \\(  - 2)

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>

<em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>

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9600 is invested at 8% per annum simple interest for 5 years​
vodomira [7]

Answer:

$3,840

Step-by-step explanation:

9600 x 0.08 =  768 per years (assuming flat rate)

768x5= 3,840

5 0
3 years ago
Read 2 more answers
Determine the ratio in which the point (–6, m) divides the join of A(–3, –1) and B(–8, 9). Also, find the value of m.
PSYCHO15rus [73]

Answer:

Ratio = 3 : 2 and value of m = 5.

Step-by-step explanation:

We are given the end points ( -3,-1 ) and ( -8,9 ) of a line and a point P = ( -6,m ) divides this line in a particular ratio.

Let us assume that it cuts the line in k : 1 ratio.

Then, the co-ordinates of P = ( \frac{-8k-3}{k+1},\frac{9k-1}{k+1} ).

But, \frac{-8k-3}{k+1} = -6

i.e. -8k-3 = -6k-6

i.e. -2k = -3

i.e. k = \frac{3}{2}

So, the ratio is k : 1 i.e \frac{3}{2} : 1 i.e. 3 : 2.

Hence, the ratio in which P divides the line is 3 : 2.

Also, \frac{9k-1}{k+1} = m where k = \frac{3}{2}

i.e. m = \frac{\frac{9 \times 3}{2}-1}{\frac{3}{2}-1}

i.e. m = \frac{27-2}{3+2}

i.e. m = \frac{25}{5}

i.e. m = 5.

Hence, the value of m is 5.

4 0
3 years ago
Read 2 more answers
Can someone please help me find the value of x
Nadya [2.5K]

Answer:

its approximately 55 cos you subtract 13 from 92

Step-by-step explanation:

8 0
3 years ago
The angle bisector of ∠ACD in rhombus ABCD makes a 64° angle with the diagonal BD. Find the measure of ∠BAD.
saveliy_v [14]
The complete question in the attached figure

we know that
the diagonals of a rhombus intersect to form right angles, 
so
angle ACE is ----------> (90°-64°)-----------> 26° 
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°

 The diagonals are angle bisectors to the opposite corners
so 
ACD = ACB = 52° 
and 
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so 
BAD = BCD = 104°

the answer is 
angle BAD=104°

3 0
3 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
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