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Tema [17]
3 years ago
14

PLEASE HELP!! please do all steps! i’ll mark as brainliest!!!

Mathematics
2 answers:
aalyn [17]3 years ago
8 0

Answer:

-3x⁴ - 9x³ + 15x² = -3x² (x² + 3x -5)

10x³ -35x² + 6x - 21 = (2x - 7) (5x² + 3)

Step-by-step explanation:

-3x⁴ - 9x³ + 15x² = -3x² (x² + 3x -5)

10x³ -35x² + 6x - 21 = (2x - 7) (5x² + 3)

pishuonlain [190]3 years ago
3 0

Answer: 1. 3x^2(-x^2-3x+5). 2. (2x-7)(5x^2+3)

Step-by-step explanation:

(1) Find the greatest common factor - 3x^2. Simplify as much as possible.

(2) Split 10x^3 - 35x^2 and 6x-21 into two separate groups. Factor each group separately to get 5x^2(2x-7) and 3(2x-7). The numbers in the parentheses should be the same for each group - (2x-7). Take the numbers outside of the parentheses and put them together to get (5x^2+3). Your final answer will be (2x-7)(5x^2+3).

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Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Assuming that all of the 255 sold seats were filled, then

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3 0
4 years ago
If you know how to do this pls help thankyou!
dmitriy555 [2]

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4 0
3 years ago
Una alberca, tiene las siguientes dimensiones: 15 metros de largo, 4 metros de ancho y una profundidad de 1.8 metros. Si se dese
snow_tiger [21]

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Step-by-step explanation:

7 0
3 years ago
7b ÷ 12 = 4.2                  What is b?
saw5 [17]
\frac{7b }{12} = 4.2 \ \ /*12 \\ \\7b=4.2*12\\ \\7b= 50.4 \ \ \/:7\\ \\\frac{7}{7} \ b= \frac{50.4 }{7}\\ \\b= 7.2


5 0
3 years ago
Read 2 more answers
Justin walked 3 miles north and 6 miles west. starting from the same point, tina walked 2 miles south and 4 miles east. how far
Darya [45]
Basically, Justin and Tina's paths form two right-angled triangles whose hypotenuses(?) form a straight line between their end points. Therefore we need to find the two distances from the starting point and add them.
Justin walked 3 miles north and 6 miles west so his distance from the start is the square root of 9+36 or 45. This can be simplified to 3√5. 
Tina walked 2 miles south and 4 miles east so her distance from the starting point is the square root of 4 + 16 or 20. This can be written as 2√5.
If we add these two distances together we get 5√5. Hence, Justin and Tina are 5√5 miles away from each other.
6 0
4 years ago
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