Write the contrapositive of the statement below.

1 answer:

8 0

If a triangle does not have one angle greater than 90Â°, then it is not an obtuse triangle. Remember that you create a contrapositive by inverting and swapping both terms. So if you have if A then B the contrapositive would be if not-B then not-A Since you've been given "If a triangle is an obtuse triangle, then it has one angle with measure greater than 90Â°" the contrapositive would be something like "If a triangle has no angles with a measure greater than 90Â°, then it is not an obtuse triangle." So, now look at the available choices and see what matches in intent even if it's not phrased exactly the same. The option "If a triangle does not have one angle greater than 90Â°, then it is not an obtuse triangle." matches the intent of the contrapositive that we constructed independently and is the correct answer.

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Which is true regarding the system of equations? x minus 4 y = 1. 5 x minus 20 y = 4.

goldfiish [28.3K]

Answer:

No solution

Step-by-step explanation:

x - 4y = 1 --> (1)

5x - 20y = 4 --> (2)

y = (¼)x - ¼ --> (1)

y = (¼)x - ⅕ --> (2)

Since these are 2 parallel lines with different y-intercepts, they will never meet

3 0

2 years ago

Read 2 more answers

Y = 7x - 15 y = 4x - 12

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

7x - 15 = 4x - 12

3x - 15 = -12

3x = 3

x = 1

y = 7(1) - 15

y = 7 - 15

y = -8

(1, -8)

3 0

3 years ago

Plz help and explain

vovikov84 [41]

To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.

We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.

The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.

Therefore
Area of band
$=(x+10)^2-x^2$ [recall $(a+b)^2=a^2+2ab+b^2$
$=x^2+20x+100-x^2$
$=20x+100$ or 20(x+5) if you wish.

8 0

3 years ago

For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr

pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables $X_i$ with the following distribution:

$X_i Bin (1,p) = Be(p)$ bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this: