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3 years ago

Which of the following equations represents a linear NON - proportional function?

Mathematics

2 answers:

love history [14]3 years ago

4 0

Y=x9 one hope that helps

HACTEHA [7]3 years ago

4 0

Y=x9 because for it to be a proportional relationship, it always has to be in the form y=mx or y=mx+b

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4 years ago

1) Para que valores reais de x o ponto P (3x -6, 2x +4) pertence ao 4º quadrante?

skelet666 [1.2K]

Answer:

There are no real values of x for point P to belong to the 4 quadrant

Step-by-step explanation:

The question in English is

To what real values of x does the point P (3x -6, 2x +4) belong to the 4th quadrant?

we know that

A point in the fourth Quadrant has the x-coordinate positive and the y-coordinate negative

we have the point

P (3x-6, 2x+4)

$3x-6 > 0$ ----> inequality A ( x-coordinate must be positive)

$2x+4 < 0$ ---> inequality B ( y-coordinate must be negative)

Solve Inequality A

$3x-6 > 0$

$3x > 6$

$x > 2$ -----> (2,∞)

Solve Inequality B

$2x+4 < 0$

$2x < -4$

$x < -2$ ----> (-∞,-2)

The solution of the system is

(-∞,-2) ∩ (2,∞)

therefore

The system has no solution

There are no real values of x for point P to belong to the 4 quadrant

3 0

4 years ago

Given: m∠AEB = 45° ∠AEC is a right angle. Prove: bisects ∠AEC. Proof: We are given that m∠AEB = 45° and ∠AEC is a right angle. T

NNADVOKAT [17]

Answer:

The proof is explained below.

Step-by-step explanation:

Given ∠AEB=45° and also ∠AEC is right angle i.e ∠AEC=90°

we have to prove that EB is the angle bisector.

In the right angled triangle AEC,

∠AEC=90° and also ∠AEB=45°

∵ ∠AEB+∠BEC=∠AEC

⇒ 45° + ∠BEC = 90°

By subtraction property of equality

∠BEC = 45°

Hence, ∠AEB = ∠BEC = 45°

The angle ∠AEB equally divides by the line segment EB therefore, the line segment EB is the angle bisector of angle ∠AEB.

7 0

3 years ago

Read 2 more answers