Od=125
2 answers:
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Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M± where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12± =12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
<h3>Answers:</h3>
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Explanation:
The scale factor is 2, which means we double each coordinate of each point. The general rule is with k = 2. So we can say the more specific dilation rule is
Something like W(-2,2) moves to W ' (-4, 4) after multiplying each coordinate by 2. Do the same for the other points as well.
The given preimage points
- V = (-2, -1)
- W = (-2, 2)
- X = (0, 2)
- Y = (3, -1)
will dilate to the corresponding image points
- V ' = (-4, -2)
- W ' = (-4, 4)
- X ' = (0, 4)
- Y ' = (6, -2)
as shown below. This causes the image to be larger compared to the preimage (since the scale factor is larger than 1). Any given point is twice as far from the origin as compared to before, which in turn means the distance between any two points is twice as much.