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3 years ago

Use the Distributive Property to expand the following expressions.

Mathematics

1 answer:

blondinia [14]3 years ago

3 0

Answer:

Step-by-step explanation:

Distributive property: a(b +c)=(a*b )+(a*c)

a) 2(y + 5x) = y*2 + 5x*2

= 2y + 10x

b) 0.4(x + 2) = x*0.4 + 2*0.4

= 0.4x + 0.8

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I am having trouble figuring out this math problem. I have tried every equation that I can think of the problem states 6×-3=5×+7

stellarik [79]

You would need to combine like terms to find your answer.
6x - 3 = 5x + 7

You would subtract 5x from both sides. Remember, x = 1x
x - 3 = 7

Lastly, you would add 3 to both sides.
x = 10

I hope this helps!

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4 years ago

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Please help me with #4 I need to solve this equation :/ it's confusing

Vera_Pavlovna [14]

First u gotta estimate what the answer u think it is. Then u turn the 2 into an 8 by multiplying both the numerator (which is 1) and denominator (which is 2) by 4 to make it 8. U then get the answer 5 4/8 and u then subtract the 5 4/8 with the 5/8 to get the answer. This was only for the first one tho!!!

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3 years ago

(X^2+x-6)(2x^2+4x) factor completely

MissTica

Answer:

$2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring $x^2+x-6$ .

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For $ax^2+bx+c$ we need to find u, v > $u\cdot \:v=a\cdot \:c$ and $u+v=b$ which we will group into $\left(ax^2+ux\right)+\left(vx+c\right)$ .

The values we have are... $a=1,\:b=1,\:c=-6$ and $u\cdot v=-6,\:u+v=1$ .

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

$\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow \mathrm{True}$

$\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow \mathrm{False}$

Therefore $u=3,\:v=-2$ .

Now we want to $\mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right)$ . Which is $\left(x^2-2x\right)+\left(3x-6\right)$ .

Now we must factor x from $x^2-2x$ .

Lets apply the exponent rule of $a^{b+c}=a^ba^c$ which means $x^2=xx$ .

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of $3x-6$ .

Rewrite 6 as 3 * 2. $3x-3\cdot \:2$ .

Now factor out the common term of 3 > $3\left(x-2\right)$ .

$x\left(x-2\right)+3\left(x-2\right)$ > Factor out the common term of x - 2 > $\left(x-2\right)\left(x+3\right)$ .

Now lets factor $2x^2+4x$ .

Apply the previous exponent rule of $a^{b+c}=a^ba^c$ > $x^2=xx$ > $2xx+4x$ .

Now rewrite 4 as 2 * 2 > $2xx+2\cdot \:2x$ .

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get $2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$ .

Hope this helps!

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3 years ago

< J and < M are base angles of isosceles trapezoid JKLM. If measure < J = 20x +9 and m < M= 14x +15, find measure &l

Kazeer [188]

The base angles of an isosceles trapezoid are equal. Therefore:
20x + 9 = 14x + 15
6x = 6
x = 1
So, the base angles both equal 29 degrees.
In a trapezoid, the sum of the angles attached to the same leg always = 180 degrees.
Therefore, angle K and angle L equal 151 degrees.

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3 years ago

I need the answer plzzz I really need it plzz help me

aleksklad [387]

I honestly don’t know good day

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3 years ago

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