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Given coordinates of the triangle: J(-4,1), K(-4,-2) and L(-3,-1).
We are given that image is rotated 90° counterclockwise about the origin.
In order to find the new coordinates of rotation 90°counterclockwise about the origin, we can apply rule (h, k) ---> (-k,h).
Where (h,k) are the coordinates of original image on axes and (-k,h) are the coordinates of rotated image.
In resulting coordinates of the image first swap the x and y coordinates of the original image and then make the sign opposite of each x-coordinate.
On applying rule (h, k) ---> (-k,h), we get
<h3>J(-4,1) --> J'(-1,-4).</h3><h3>K(-4,-2) --> K'(2,-4).</h3><h3>L(-3,-1). --> L'(1,-3).</h3><em>Blue image is rotation of 90°counterclockwise about the origin. </em>
2) Rule for reflection about y-axis would be (h, k) ---> (-h,k).
On applying rule (h, k) ---> (-h,k), we get
<h3>J(-4,1) --> J'(4,1)</h3><h3>K(-4,-2) --> K'(4,-2).</h3><h3>L(-3,-1). --> L'(3,-1).</h3><em>Red image is reflection across the y-axis.</em>
Option C: (x-4)^2+(y-1)^2 = 4 is the right answer
Step-by-step explanation:
Given
Center = (h,k) = (4,1)
Radius = r = 2
The equation of circle in standard form is:
Putting the values of h, k and r
Hence,
Option C: (x-4)^2+(y-1)^2 = 4 is the right answer
Keywords: Equation of circle
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