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Gennadij [26K]
3 years ago
11

The ability to learn a new computer software program is to ____________ as knowledge of state capitals is to _____________.

Computers and Technology
1 answer:
Montano1993 [528]3 years ago
8 0
<span>The ability to learn a new computer software program is to ADAPT as knowledge of state capitals is to COMMIT. Learning something new is to adapt and take time to study and learn what needs to be done in order for the task you wish to happen. To have knowledge of a specific thing, is to committing that face to your memory.</span>
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In a Windows environment, __________ is a powerful tool that enables security administrators to share user and group definitions
spayn [35]

Answer:

Active Directory

Explanation:

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You use_____ to view an XPS file
Katyanochek1 [597]
Firefox
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Which option will enable Mina to apply several formats to the spreadsheet cells at the same time?
madam [21]
Applying a cell style will enable Mina to apply several formats to the spreadsheet cells at the same time.  <span>To apply several formats in one step, and to make sure that cells have consistent formatting, you can use a cell style. A cell style is a defined set of formatting characteristics, such as fonts and font sizes, number formats, cell borders, and cell shading. </span>
4 0
3 years ago
You are a psychologist who needs to provide a qualitative evaluation for IQ scores. Create a program that takes IQ scores (one a
dsp73

Answer:

Check the explanation

Explanation:

#include <iostream>

#include <iomanip>

using namespace std;

int getIQ(); // return the score

void printEvaluation(int);

int main()

{

   int IQ = 0;

   IQ = getIQ();

   

   printEvaluation(IQ);

   return 0;

}

int getIQ()

{

   int score = 0;

   cout << "Please enter your IQ Score to receive your IQ Rating:\n";

   cin >> score;

   

   return score;

}

void printEvaluation(int aScore)

{

   cout << "IQ Score: " << aScore << " IQ Rating: ";

   

   if (aScore <= 100)

   {

       cout << "Below Average\n";

   }

   else if (aScore <= 119)

   {

       cout <<"Average\n";

   }

   else if (aScore <= 160)

   {

       cout << "Superior\n";

   }

   else if (aScore >= 160 )

   {

       cout << "Genius\n";

   }

}

4 0
3 years ago
I WILL GIVE BRAINLIEST
Lostsunrise [7]

Answer:

i know but you to help me ok this answer b

3 0
3 years ago
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