Give 3 advantages of using shortcut key, especially in MS Office.

In C, a switch construct can have ________ number of default case(s). *

azamat

I think so that it will be zero or more

7 0

3 years ago

Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,

Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary denary or decimal

11111111 = 2⁸ = 256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s = /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1  1  1 1 1 1

128 64 32 16 8 4 2 1

step 3

in the ip network address: 198.16.0.0/19 (subnet representation) we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts+16: 198.16.16.0 - 198.16.31.255

+16: 198.16.32.0- 198.16.47.255 etc

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11111000.000000 /21

now we have added 5 1s in the third field to reserve 11 0s

subnet mask: 255.255.8.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1  1 1 1

128 64 32 16 8  4 2 1

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (subnet representation) we increment this using 8

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts +16: 198.16.24.0- 198.16.31.255

+16: 198.16.32.0- 198.16.112.255 etc

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1 1 1 1

128 64 32 16 8 4 2 1

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts +16: 198.16.40.0- 198.16.55.255

+16: 198.16.56.0- 198.16.71.255 etc

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11100000.000000 /19

now we have added 3 1s in the 3rd field to reserve 13 0s

subnet mask: 255.255.32.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1  1  1 1 1 1 1

128 64 32  16 8 4 2 1

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts +16: 198.16.72.0- 198.16.103.255

+16: 198.16.104.0- 198.16.136.255 etc

5 0

3 years ago

Write a program that will predict the size of a population of organisms. The program should ask the user for the starting number

sineoko [7]

Answer:

// using c++ language

#include "stdafx.h";

#include <iostream>

#include<cmath>

using namespace std;

//start

int main()

{

//Declaration of variables in the program

double start_organisms;

double daily_increase;

int days;

double updated_organisms;

//The user enters the number of organisms as desired

cout << "Enter the starting number of organisms: ";

cin >> start_organisms;

//Validating input data

while (start_organisms < 2)

{

cout << "The starting number of organisms must be at least 2.\n";

cout << "Enter the starting number of organisms: ";

cin >> start_organisms;

}

//The user enters daily input, here's where we apply the 5.2% given in question

cout << "Enter the daily population increase: ";

cin>> daily_increase;

//Validating the increase

while (daily_increase < 0)

{

cout << "The average daily population increase must be a positive value.\n ";

cout << "Enter the daily population increase: ";

cin >> daily_increase;

}

//The user enters number of days

cout << "Enter the number of days: ";

cin >> days;

//Validating the number of days

while (days<1)

{

cout << "The number of days must be at least 1.\n";

cout << "Enter the number of days: ";

cin >> days;

}

//Final calculation and display of results based on formulas

for (int i = 0; i < days; i++)

{

updated_organisms = start_organisms + (daily_increase*start_organisms);

cout << "On day " << i + 1 << " the population size was " << round(updated_organisms)<<"."<<"\n";

start_organisms = updated_organisms;

}

system("pause");

return 0;

//end

}

Explanation:

6 0

3 years ago

Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less

Ad libitum [116K]

Answer:

#include<iostream>//library inclusion

using namespace std;

int main()

{

int userInput;

do//start of do while loop

{

cout << "Enter a number less than a 100" << endl;

cin >> userInput;

if (userInput < 100) //condition

{

cout << "YOu entered less than a hundred: " << userInput << endl;

}

else

{

cout << "your number is greater than 100" << endl;

}

} while (userInput > 100);//condition for do while

return 0;//termination of int main

}

Explanation:

The program has been commented for you. The do-while loop enters the first loop regardless of the condition. Then after the first iteration, it checks for the condition. If the condition is being met, it will iterate through, again. Otherwise it will break out of the loop and land on the "return 0;" line. Which also happens to be the termination of the program in this case. The if-else condition is used for the user to see when prompted.

6 0

3 years ago

Since the 1960s, there have been five major generations, or cycles, of computing. Which represents those generations in order?

sergiy2304 [10]

Answer:a) Mainframes, miniframes, PCs, desktop Internet computing, mobile computing

Explanation: The hierarchy of the computers or computing are in the generation is:-

Mainframe:-designed for the execution of huge data processing , storage and execution.
Miniframe:-has similar functioning as the mainframe but on smaller scale and version.
Personal computer(PC):-It is designed for the individual purpose and according the need of the user.
Mobile computing:-computing that can be done on the mobile phone similar to the computing on the personal computer
Internet computing:-the computing of the mobile and computer system with the facility of the internet connectivity.

7 0

3 years ago