Answer:
Step-by-step explanation:
The picture of the question in the attached figure
we know that
In the right triangle of the figure
----> by SOH (opposite side divided by the hypotenuse)
using a calculator
Which ordered pair is the vertex of y=|x+5|-1
1 answer:
Y = I x + 5 I -1
f(-x) : I x + 5 I - 1
<span>I- x + 5 I - 1</span>
- f(x) = - I x + 5 I + 1
- ( I x + 5 I ) - ( -1 )
<span>- I x + 5 I + 1
</span>
f(-x) ≠ f(x) therefore I x + 5 I -1 is not an even function .
f(-x) ≠ - f(x) therefore I x + 5 I - 1 is not an odd function.
Neither even nor odd
<span>attached image</span>
hope this helps!
f(-x) : I x + 5 I - 1
<span>I- x + 5 I - 1</span>
- f(x) = - I x + 5 I + 1
- ( I x + 5 I ) - ( -1 )
<span>- I x + 5 I + 1
</span>
f(-x) ≠ f(x) therefore I x + 5 I -1 is not an even function .
f(-x) ≠ - f(x) therefore I x + 5 I - 1 is not an odd function.
Neither even nor odd
<span>attached image</span>
hope this helps!
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