Which ordered pair is the vertex of y=|x+5|-1

Mathematics

1 answer:

Alexxx [7]3 years ago

3 0

Y = I x + 5 I -1

f(-x) : I x + 5 I - 1

I- x + 5 I - 1

- f(x) = - I x + 5 I + 1

- ( I x + 5 I ) - ( -1 )

- I x + 5 I + 1

f(-x) ≠ f(x) therefore I x + 5 I -1 is not an even function .

f(-x) ≠ - f(x) therefore I x + 5 I - 1 is not an odd function.

Neither even nor odd

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hope this helps!

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This rational expression is nonequivalent. 5x / 25x^4 ; x^3 / 5x^15 True or false?????

FromTheMoon [43]

It is nonequivalent. Figure it out this way. Think about what number has to be multiplied by both the numerator and the denominator of $\frac{5x}{25x^4}$ to get to $\frac{x^3}{5x^15}$ . It has to be the samee number for the one expression to be equivalent to the other. To get from 5x to x^3, we have to multiply by 1/5x^2. When we do that we get x^3. Good. Now we have to multiply the denominator by the same thing, 1/5x^2. $25x^4(\frac{1}{5}x^2)=5x^6$ . As you can see, they are not equivalent.