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3 years ago

Solve for the values of x by factoring. x² – 52 - 24=O

Mathematics

1 answer:

svet-max [94.6K]3 years ago

8 0

Answer:

26 plus or minus 10 times the square root of 7

Step-by-step explanation:

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2+2 please help meeeeeee

pav-90 [236]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which function has an inverse that is also a function?

dimaraw [331]

Answer:

g(x) = 2x – 3 is the function has an inverse that is also a function.

The correct option is A.

Inverse function;

The inverse of a function is the equation where x and y have switched places.

Here g(x) = 2x - 3 has inverse x = 2y - 3 which simplifies to;

$y = \frac{x-3}{2}$

$y = \frac{1}{2} x - \frac{3}{2}$

k(x) = - $9x^{2}$ has the inverse x = $-9y^{2}$ which simplifies to;

$y =\sqrt{ \frac{x}{-9} }$

f(x) = |x+2| is an absolute value function.

w(x) = -20 does not have an inverse which is a function.

Therefore

The function has an inverse that is also a function is g(x) = 2x – 3.

#SPJ1

3 0

2 years ago

PLSSS HELPPP MARKING BRAINLIST !!!!!!

ioda

Answer:

First Option; 40,

Second Option; x = 3,

Third Option; x = - 5,

Fourth Option; x = 0

Step-by-step explanation:

Given the expression x^2 + 3 * ( x + 4 ), where x = 4;

x^2 + 3 * ( x + 4 ) ⇒ Substitute the value of 4 in replacement of x,

( 4 )^2 + 3 * ( 4 + 4 ) ⇒ Add the terms in ( ), taking 4^2 at the same time,

16 + 3 * ( 8 ) ⇒ By PEMDAS, multiply 3 by 8 first,

16 + 24 ⇒ And now add the remaining terms,

Solution; 40

This next equation is given to be 5 * ( 2x - 1 ) = 25, where we must solve for x;

5 * ( 2x - 1 ) = 25 ⇒ Distribute the 5 to the terms in ( ),

10x - 5 = 25 ⇒ Add 5 on either side of the equation,

10x = 30 ⇒ Divide 10 on either side of equation,

Solution; x = 3

Here we must solve for the value of x provided the equation 6x + 4 - x = 2x - 11;

6x + 4 - x = 2x - 11 ⇒ Add 11 on either side,

6x + 15 - x = 2x ⇒ Add x on either side of equation,

6x + 15 = 3x ⇒ Subtract 6x on either side,

15 = - 3x ⇒ Divide 3 on either side,

Solution; x = - 5 

Now we are given the equation 4 - ( 3x + 4 ) = - 9x, solving for the value of x;

4 - ( 3x + 4 ) = - 9x ⇒ Distribute the - 1 to all terms in ( ),

4 - 3x - 4 = - 9x ⇒ Add 3x on either side of equation,

4 - 4 = - 6x ⇒ Subtract 4 from 4,

0 = - 6x ⇒ Divide - 6 on either side,

Solution; x = 0

4 0

3 years ago

PLEASE HELP!!!

Nostrana [21]

Can you take a pic of the question because the link is not working

5 0

3 years ago

Determine the domain of the function (fog) (x) where f(x) = 3x-1/x-4 and g(x)=x+1/x

Mrac [35]

Answer:

$(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)$

Step-by-step explanation:

The given functions are $f(x)=\frac{3x-1}{x-4}$ and $g(x)=\frac{x+1}{x}$ .

We now composed the two functions to find:

$(f\circ g)(x)=f(g(x))$

$\implies (f\circ g)(x)=f(\frac{x+1}{x})$

$\implies (f\circ g)(x)=\frac{3(\frac{x+1}{x})+1}{\frac{x+1}{x}-4}$

$\implies (f\circ g)(x)=\frac{4x+3}{1-3x}$

This function is defined if the denominator is not zero.

$1-3x\ne0$

$x\ne\frac{1}{3}$

We write this in interval notation as:

$(-\infty,\frac{1}{3})\cup (\frac{1}{3},\infty)$

We need to be cautious here as x=0 is not in the domain of g(x).

Therefore the domain of $(f\circ g)(x)$ is

$(-\infty,0)\cup(0, \frac{1}{3})\cup (\frac{1}{3},\infty)$

4 0

3 years ago