3 years ago

Please I need help!!!!!!!!

Mathematics

2 answers:

seropon [69]3 years ago

7 0

Answer:

10 is the correct answer

nexus9112 [7]3 years ago

5 0

Answer:

Go with the third option 10!

i hope this helped!

You might be interested in

What is the equation of the parabola with focus (4,1) and directrix y= 2?

mariarad [96]

It’s A I think I had it on a recent test :) I’m not sure tho

8 0

3 years ago

To convert 8.5 yards to feet which ratio could you multiply by

uranmaximum [27]

8.5 yd/1 * 3ft/1yd ................

7 0

3 years ago

Read 2 more answers

Can someone help me with 3,4 and 5? For 3 and 4 it's asking "what is the volume of each solid? Round to the nearest tenth if nec

Marianna [84]

Answer:

the answer 3,b

4,f

5,c

7 0

3 years ago

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago

Please don’t answer this im testing something

prisoha [69]

Answer:

uhhhhhhhhhhhhhhhhhhhhhhh

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers