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EleoNora [17]
3 years ago
15

P(A) = 7/20 P(B) = 7/20 P(A or B) = 49/80, P(A and B)= ?​

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer:

P(A and B) = 7/80

Step-by-step explanation:

The given values of the probabilities of the different events are;

P(A) = 7/20

P(B) = 7/20

P(A or B) = 49/80

P(A and B) = Required

We have by probability theory for any event;

P(A or B) = P(A) + P(B) - P(A and B)

Therefore;

P(A and B) = P(A) + P(B) - P(A or B)

Plugging in the values gives;

P(A and B) = 7/20 + 7/20 - 49/80 = 7/80

∴ P(A and B) = 7/80

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Step-by-step explanation:

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sub in a point and gradient/slope to get c

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y=3x-4

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Hans is staining the wooden floor of a court. The court is in the shape of a rectangle. Its length is feet and its width is feet
Tomtit [17]

Answer:

number of cans Raina will be needed in court floor is 14 cans

Step-by-step explanation:

CHECK THE COMPLETE QUESTION BELOW;

Raina is staining the wooden floor of a court. The court is in the shape of a rectangle. Its length is 46 feet and its width is 35 feet. Suppose each can of wood stain covers 115 square feet. How many cans will she need to cover the court?

CALCULATION;

Given:

length of the rectangular shape =46 feet

width of the the rectangular shape = 35 feet.

The floor of the court room is having a rectangular shape, then we need to calculate the surface Area of the rectangular shape first in order to know the number of cans that Raina will be needed

Surface Area= Length × Width

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Then to get the number of cans , we need to divide the surface Area by each can of wood stain covers which is 115 square feet,

number of cans Raina will be needed in court = 1610 square ft / 115 square ft = 14

number of cans Raina will be needed in court floor is 14cans

7 0
3 years ago
.
I am Lyosha [343]
Central angle  = 360 / 24  = 15 degrees

ARc length =  r * theta,    where theta is the angle in radians  and r = radius
                  = 15 * 15 * pi/180  
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Area of sector =  area of circle / 24  = pi*15^2 / 24 =  29.45 ft^2 
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c)The minimum value of the function occurs at x=3.

6 0
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