y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
Answer:
C
Step-by-step explanation:
Answer:
Step-by-step explanation: im pretty sure that its b so there you go
Answer:
9
Step-by-step explanation:
List out the factors of the three numbers.
18: 1, 2, 3, 6, 9, 18
36: 1, 2, 3, 4, 6, 9, 12, 18, 36
45: 1, 3, 5, 9, 15, 45
The largest number that all three of these lists share is 9, so 9 is the GCF.
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X= 7 1/3
Explanation- Take 72 and subtract 50 from that giving you 22. Then take 22 and divide it by 3 to get 7.3333333333333 (repeats) or 7 1/3
