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3 years ago

Someone please help asap

Mathematics

1 answer:

andrew-mc [135]3 years ago

6 0

Answer:

the second one

Step-by-step explanation:

because g(x) and f(x) is bout the same

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Line m passes through (4, 7) and (8, 2). Line n is parallel to line m. What is the slope

Harlamova29_29 [7]

X= 4 and Y=-5
or
X=-4 and Y=5

4 0

3 years ago

Given: triangle LNK, m of angle NLK =72 degrees. m of angle N=58 degrees. MP is perpendicular bisector of side LK and intersects

sweet-ann [11.9K]

Answer:

50°

Step-by-step explanation:

Given triangle LNK

m∠NLK = 72°
m∠LNK = 58°
m∠LKN = ?

Interior angles sum to 180°

m∠NLK + m∠LNK + m∠LKN = 180°
72° + 58° + m∠LKN = 180°
m∠LKN = 180° - 130°
m∠LKN = 50°

4 0

3 years ago

Which logarithmic equation is equivalent to the exponential equation below?

Nataly_w [17]

With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)

8 0

3 years ago

Read 2 more answers

What is the middle term of the product of (x + 5)(x + 2)? ??

kotykmax [81]

Answer:

Step-by-step explanation:

Polynomial distribution:

(x + 5) (x + 2)

x^2 + 2x + 5x + 10

x^2 + 7x +10

8 0

2 years ago

Read 2 more answers

To find the extreme values of a function f(x,y) on a curve xequalsx(t), yequalsy(t), treat f as a function of the single vari

pychu [463]

Answer:

Absolute maximum is 2

Absolute minimum at -2

Step-by-step explanation:

The given parametric functions are:

$x=2\cos t,y=2\sin t$

By the chain rule:

$f'(t)=\frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$\frac{df}{dt} =\frac{2 \cos t}{-2\sin t} =-\cot(t)$

At fixed points, $f'(t)=0$

$\implies -\cot (t)=0$

This gives $t=\frac{\pi}{2} ,\frac{3\pi}{2}$ on $0\le t\le 2\pi$

This implies that the extreme points are $(2\cos \frac{\pi}{2}, 2\sin \frac{\pi}{2})=(0,2)$ and $(2\cos \frac{3\pi}{2}, 2\sin \frac{3\pi}{2})=(0,-2)$

By eliminating the parameter, we have $x^2+y^2=4$

This is a circle with radius 2, centered at the origin.

Hence (0,2) is an absolute maximum ,at $t=\frac{\pi}{2}$ and (0,-2) is an absolute minimum at $t=\frac{3\pi}{2}$

7 0

3 years ago