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telo118 [61]
3 years ago
6

Which graph represents the function f (x) = StartFraction 5 minus 5 x squared Over x squared EndFraction? On a coordinate plane,

a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens up and to the left in quadrant 2. On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrants 1 and 4, and the other curve opens up and to the left in quadrants 2 and 3. On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrants 1 and 2, and the other curve opens up and to the left in quadrant 3. On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrants 3 and 4.
Mathematics
1 answer:
trapecia [35]3 years ago
4 0

9514 1404 393

Answer:

2. On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrants 1 and 4, and the other curve opens up and to the left in quadrants 2 and 3

Step-by-step explanation:

Technically, the curve is not a hyperbola. A hyperbola is of the form 1/x; this one is of the form 1/x².

The function can be simplified to ...

  f(x) = 5/x² -5

which is a "hyperbola" with a vertical asymptote at x=0 and a vertical translation of -5 units to bring parts of it into the 3rd and 4th quadrants.

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%3F%7D%7B5%7D%20%2A%20%5Cfrac%7B10%7D%7B8%7D%20%3D1.5%5C%5C" id="TexFormula1" title=
Serggg [28]

Answer:

\boxed{\sf \huge \boxed{ \sf ?} = 6}

Step-by-step explanation:

\sf Solve  \: for \: \boxed{ \sf ?} :  \\  \sf \implies \frac{\boxed{ \sf ?}}{5}  \times  \frac{10}{8}  = 1.5 \\  \\  \sf  \implies \frac{\boxed{ \sf ?} \times 10}{5 \times 8}  = 1.5 \\  \\  \sf \frac{10}{5}  =  \frac{ \cancel{5} \times 2}{ \cancel{5}}  = 2 :  \\  \sf \implies  \frac{ \boxed{ \sf 2} \times \boxed{ \sf ?} }{8}  = 1.5 \\  \\  \sf \frac{2}{8}  =  \frac{ \cancel{2}}{ \cancel{2}  \times 4}  =  \frac{1}{4}  :  \\  \sf \implies \frac{\boxed{ \sf ?}}{ \boxed{ \sf 4}}  = 1.5 \\  \\  \sf Multiply  \: both  \: sides \:  of \:  \frac{\boxed{ \sf ?}}{4}  = 1.5 \: by \: 4 :  \\  \sf \implies \frac{4 \times \boxed{ \sf ?}}{4}  = 4 \times 1.5 \\  \\  \sf \frac{4 \times \boxed{ \sf ?}}{4} =  \frac{ \cancel{4}}{ \cancel{4}}  \times \boxed{ \sf ?} = \boxed{ \sf ?} :  \\  \sf  \implies \boxed{\boxed{ \sf ?}} = 4 \times 1.5 \\  \\  \sf 4 \times 1.5 = 6 :  \\  \sf \implies \boxed{ \sf ?} = 6

4 0
3 years ago
Last year the highest temperature in a city was recorded as 23ºC, and the lowest temperature was recorded as -10ºC. How many deg
DerKrebs [107]

33 degrees C

Step-by-step explanation:

On the integer scale, the numeric values can be added thus

23 to -10

23 to 0 and 0 to -10

23-0 = 23

0 -(-10) = 10

23 + 10 = 33

Thus, 33 degree C is the difference between the two temperatures.

5 0
3 years ago
Abigail flipped a coin 20 times, and it landed with heads facing up 13 times. What percent of the coin flips landed with heads f
DIA [1.3K]
65% of the coins flipped landed with heads facing up because 13 were faced up out of 20.

Divide:
13/20=0.65=65%

Hope this helped☺☺
5 0
3 years ago
Solve for x. 19x+rx=−37x+w
pshichka [43]
Get all the x terms on one side, and the w on the other.
Add 37x on both sides to get 56x+rx=w.
Use the distributive property backwards to get x(56+r)=w.
Divide by 56+r on both sides to get x=w/(56+r)
3 0
3 years ago
What is the equation for the graph shown?
alexandr1967 [171]

Answer:

the first one is the answer

8 0
2 years ago
Read 2 more answers
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