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3 years ago

Can anyone tell me the answer please ??

Mathematics

1 answer:

Nutka1998 [239]3 years ago

7 0

-8

the rate of change is -2 and the difference in y from 4 to 8 is 4 so 4 * -2

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I really need help asap show all work

Triss [41]

Note: Consider we need to find the factor form of the given expression by taking out the GCF.

Given:

The expression is:

$-42k^3+24k^4+12k^5$

To find:

The factor form of the given expression.

Solution:

We have,

$-42k^3+24k^4+12k^5$

It can be written as:

$=6k^3(-7)+6k^3(4k)+6k^3(2k^2)$

Taking out the greatest common factor (GCF), we get

$=6k^3(-7+4k+2k^2)$

Therefore, the factor form of the given expression is $6k^3(-7+4k+2k^2)$ .

8 0

2 years ago

Eric rented a truck for one day the base fee was 16.95 for additional charge of .76 cents for each mile driven eric had to pay 1

goldenfox [79]

Answer:

178 miles

Step-by-step explanation:

Let Eric has driven d miles.

As the rate of charge of driving the truck = 76 cents /mile

So, the charge of driving the truck for d miles = 76d cents= $0.76d

The base fee of the truck was $16.95.

Total money paid at the time of returning the truck = $152.23

So, 16.95+0.76d=152.23

0.76d= 152.23-16.95=135.28

d=135.28/0.76

d=178

Hence, he drives 178 miles.

8 0

2 years ago

In the past, Samuel got paid $59,950 annually. Since switching to a new career, he has been making 18% more. How much does Samue

Basile [38]

The correct answer is $70,741 :)

3 0

2 years ago

Read 2 more answers

The sum of a rational number and an irrational number equals:

WINSTONCH [101]

Answer: is an irrational number

Step-by-step explanation:

Like adding three to pi (3.14159265358979323846264....)is still going to be irrational

3 0

2 years ago

Read 2 more answers

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

4 0

3 years ago