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Savatey [412]
3 years ago
15

Can anyone tell me the answer please ??

Mathematics
1 answer:
Nutka1998 [239]3 years ago
7 0
-8 

the rate of change is -2 and the difference in y from 4 to 8 is 4 so 4 * -2
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A website-hosting service charges a one-time setup fee of $20 plus d dollars for each month. A business owner paid $70 for the f
alina1380 [7]

Answer:

D= 10 Dollars each month

Step-by-step explanation:

You find this answer by subtracting the one time fee of 20 from the total payed of 70, leaving you with 50.  You then divide that 50$ by 5 months.

5 0
3 years ago
Which of these strategies would eliminate a variable in the system of equations? \begin{cases} 6x + 5y = 1 \\\\ 6x - 5y = 7 \end
frez [133]

Answer:

Option A and B are correct

Step-by-step explanation:

We have to add here

6x+5y=1.

6x-5y=7

sow e will get 12x=8 , x=8/12=2/3

Option A  is correct.

If We substract bottom from furst then

6x+5y=1

-6x+5y=-7

10y=-6

y=-6/10=-3/5

we put y=-3/5 in any equation and find x

6x+5(-3/5)=1

6x=4

x=4/6=2/3

So Option B also correct.

5 0
3 years ago
at an elementary school 99 students are in 1st grade represent 33% of the students at the school, how many students are at the s
Kitty [74]

Answer:

300 is the student strength of the school

Step-by-step explanation:

99 of total students=33%

total students=99*100/33

total student=9900/33

total student=300 students

7 0
3 years ago
To estimate a population mean, the sample size needed to provide a margin of error of 3 or less with a 95% confidence when the p
Over [174]

Answer:

The minimum sample needed to provide a margin of error of 3 or less is 52.

Step-by-step explanation:

The confidence interval for population mean (<em>μ</em>) is:

\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

The margin of error is:

MOE= z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

<u>Given:</u>

MOE = 3

<em>σ </em>= 11

The critical value for 95% confidence interval is: z_{\alpha /2}=1.96

**Use the <em>z</em>-table for critical values.

Compute the sample size (<em>n</em>) as follows:

MOE= z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\\3=1.96\times \frac{11}{\sqrt{n}}\\n=(\frac{1.96\times11}{3} )^{2}\\=51.65\\\approx52

Thus, the minimum sample needed to provide a margin of error of 3 or less is 52.

7 0
3 years ago
I need help with math
Keith_Richards [23]

\frac{1}{5}  +  \frac{3}{4}  \times  \frac{3}{5}  =  \\

\frac{1}{5}  +  \frac{9}{20}  =  \\

\frac{4}{20}  +  \frac{9}{20}  =  \\

\frac{13}{20}  \\

4 0
2 years ago
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