Ask question

Ask question

All categories

3 years ago

12

Answer my math question correctly!

1 answer:

sladkih [1.3K]3 years ago

6 0

Hey the answer to your question is 6x10^4

You might be interested in

Given: Quadrilateral DEFG

nadya68 [22]

We know that
The inscribed angle Theorem states that t<span>he inscribed angle measures half of the arc it comprises.
</span>so
m∠D=(1/2)*[arc EFG]
and
m∠F=(1/2)*[arc GDE]

arc EFG+arc GDE=360°-------> full circle

applying multiplication property of equality
(1/2)*arc EFG+(1/2)*arc GDE=180°

applying substitution property of equality
m∠D=(1/2)*[arc EFG]
m∠F=(1/2)*[arc GDE]
(1/2)*arc EFG+(1/2)*arc GDE=180°----> m∠D+m∠F=180°

the answer in the attached figure

3 0

3 years ago

Identify the correct equation that describe the relationship between a sine and cosine wave. a. v(t) = A sin (2πft + π/2) = A co

Flauer [41]

Answer:

A. v(t) = sin (2πft + π/2) = A cos (2πft)

Step-by-step explanation:

According to trigonometry friction, the following relationship are true;

Sin(A+B) = sinAcosB + cosAsinB

We will be using this relationship to check which option is true.

Wave equation is represented as shown;

y(t) = Asin(2πft±theta)

For positive displacement,

y(t) = Asin(2πft+theta)

If theta = π/2

y(t) = Asin(2πft+π/2)

y(t) = A[ sin 2πftcosπ/2 + cos2πft sin π/2]

Since sinπ/2 = 1 and cos (π/2) = 0

y(t) = A[ sin 2πft (0)+ cos2πft (1)]

y(t) = A[0+ cos2πft]

y(t) = Acos2πft

Hence the expression that is true is expressed as;

v(t) = Asin(2πft+π/2) = Acos2πft

8 0

3 years ago

Use the formula Area = (side)2 to find the area of the square.

ki77a [65]

Answer:

1. 5² is 25 yards

2. 7² is 49m

3. 8² is 64cm

4.draw a square, make one side 6 feet then do 6² which is 36feet

5. do the same thing then write 10 inches on one side and 10² is 100 inches.

6. 7x3= 21 ft

7. 5x4= 20 in.

8. 2x8= 16 yd

Step-by-step explanation:

common sense

7 0

2 years ago

Read 2 more answers

Please answer the question now in two minutes

oksian1 [2.3K]

Answer:

Coordinates of point P is $(-14,3)$ .

Step-by-step explanation:

Given that mid point of line segment $\overline {PQ}$ is at <em>M(-9, 8.5).</em>

Q is at <em>(-4, 14)</em>.

Let coordinate of P be $(x,y)$ .

Using the ratio, we can say the following:

<em>The coordinates of mid point</em> $(X,Y)$ of a line with endpoints $(x_1, y_1)$ and $(x_2, y_2)$ is given as:

$X=\dfrac{(x_1+ x_2)}{2}$

$Y=\dfrac{(y_1+ y_2)}{2}$

Using the formula for above given dimensions:

$-9 =\dfrac{x+(-4)}{2}\\\Rightarrow x = -18+4 = -14$

$8.5=\dfrac{(14+ y)}{2}\\\Rightarrow y = 17-14 =3$

So, the <em>coordinates of point P are</em> $(-14,3)$ .

6 0

3 years ago

Hank brought 2.4 pounds of apples.each pund cost $1.89. How much did hank spend on his apples?

Illusion [34]

$4.54 if all rounded out

5 0

3 years ago

Read 2 more answers