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3 years ago

WILL GIVE BRAINLIEST!!

Mathematics

1 answer:

Stels [109]3 years ago

4 0

Hello,

$m(x) = 5x + 4\\n(x) = 6 x-9\\Part\ A:\\(m + n)(x)=m(x)+n(x)=5x+4+6x-9=11x-5\\Part\ B:\\ (m-n)(x)=m(x)-n(x)=5x+4-(6x-9)=5x-6x+4+9=-x+13\\Part\ C: \\(m\ o\ n)(x)=m[n(x)]=m(6x-9)=5*(6x-9)+4=30x-45\\$

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Fittoniya [83]

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3 years ago

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If a game consists of picking a number from a bag of beans numbered 2, 3, 3, 4, and 5 and flipping a coin, which probabilities a

kykrilka [37]

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2 years ago

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A(5 1) b(1 5) and c(-3 -1) are the vertices of triangle abc. find the LENGTH of median ad

faltersainse [42]

Answer:

$\text{Length of median AD}=\sqrt{37}$

Step-by-step explanation:

We are given the vertices of triangle ABC. We need to find the length of median AD.

Please see the attachment for figure.

D is mid point of BC because median bisect the opposite side of triangle.

Using the formula of mid point. we get coodrinate of D

$\text{Mid Point :}\left ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right )$

D is mid point of B(1,5) and C(-3,-1)

$\therefore D \left ( \frac{1-3}{2},\frac{5-1}{2} \right )\Rightarrow (-1,2)$

AD is median of triangle ABC. Now we find length of median AD using distance formula of two coordinate.

$\text{Distance }=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(5,1) and D(-1,2)

$AD=\sqrt{(5+1)^2+(1-2)^2}\Rightarrow \sqrt{36+1}$

$\text{Length of median AD}=\sqrt{37}$

Thus, $\text{Length of median AD}=\sqrt{37}$

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3 years ago

PLEASE HELP

creativ13 [48]

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The third answer is the correct one. The other three answers aren't even close!

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4 years ago

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Sliva [168]

I’m not 100% but I think it could be the last table

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