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soldi70 [24.7K]
3 years ago
7

WILL GIVE BRAINLIEST!!

Mathematics
1 answer:
Stels [109]3 years ago
4 0

Hello,

m(x) = 5x + 4\\n(x) = 6 x-9\\Part\ A:\\(m + n)(x)=m(x)+n(x)=5x+4+6x-9=11x-5\\Part\ B:\\ (m-n)(x)=m(x)-n(x)=5x+4-(6x-9)=5x-6x+4+9=-x+13\\Part\ C: \\(m\ o\ n)(x)=m[n(x)]=m(6x-9)=5*(6x-9)+4=30x-45\\

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A(5 1) b(1 5) and c(-3 -1) are the vertices of triangle abc. find the LENGTH of median ad
faltersainse [42]

Answer:

\text{Length of median AD}=\sqrt{37}

Step-by-step explanation:

We are given the vertices of triangle ABC. We need to find the length of median AD.

Please see the attachment for figure.

D is mid point of BC because median bisect the opposite side of triangle.

Using the formula of mid point. we get coodrinate of D

\text{Mid Point :}\left ( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right )

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\therefore D \left ( \frac{1-3}{2},\frac{5-1}{2} \right )\Rightarrow (-1,2)

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\text{Distance }=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

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AD=\sqrt{(5+1)^2+(1-2)^2}\Rightarrow \sqrt{36+1}

\text{Length of median AD}=\sqrt{37}

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