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stira [4]
3 years ago
10

Hello! Can someone please help me solve this? I need to know how to make the graph. Thanks!

Mathematics
1 answer:
kap26 [50]3 years ago
8 0

Answer:

month us your x, and temp. is your y

type the graph into demos graph calculator.

hope this helps

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HELP ASAP PLEASE thanks youu
BlackZzzverrR [31]

Answer: Probably A

Step-by-step explanation: You need to use a ruler for this, because without one its impossible to get it exact

Using the ruler though, you'd measure each side of the wall and either use a ratio of 0.5in:4ft or multiply every 0.5in by 4ft.

6 0
3 years ago
Julia is allowed to watch no more than 5 hours of television a week. So far this week, she has watched 1.5 hours. Write and solv
Leona [35]

The inequality is used to solve how many hours of television Julia can still watch this week is x + 1.5 \leq 5

The remaining hours of TV Julia can watch this week can be expressed is 3.5 hours

<h3><u>Solution:</u></h3>

Given that Julia is allowed to watch no more than 5 hours of television a week

So far this week, she has watched 1.5 hours

To find: number of hours Julia can still watch this week

<em>Let "x" be the number of hours Julia can still watch television this week</em>

"no more than 5" means less than or equal to 5 ( ≤  5 )

Juila has already watched 1.5 hours. So we can add 1.5 hours and number of hours Julia can still watch television this week which is less than or equal to 5 hours

number of hours Julia can still watch television this week + already watched ≤ Total hours Juila can watch

x + 1.5 \leq5

Thus the above inequality is used to solve how many hours of television Julia can still watch this week.

Solving the inequality,

x + 1.5 \leq5\\\\x \leq 5 - 1.5\\\\x \leq 3.5

Thus Julia still can watch Television for 3.5 hours

5 0
3 years ago
Help Pleasee<br><br> Reflect shape A in the line x = -2
Cerrena [4.2K]

Answer: Check out the diagram below

The reflected image is shown in red.

=================================================

Explanation:

Draw a vertical line through -2 on the x axis. This is the mirror line.

Now focus on the upper right corner of the figure, which is at (-3, -1). Notice how the horizontal distance from this corner point to the mirror line is exactly 1 unit. If we move another 1 unit to the right, then we'll arrive at (-1,-1) which is where the reflected point lands or ends up.

In short, the upper right corner point (-3,-1) reflects over x = -2 to land on (-1,-1)

----------------------

As another example, the upper left corner point (-5, -1) will move exactly 4 spaces to the right to get to the mirror line. Then we move another 4 spaces to the right to get to (2,-1).

So the upper left corner (-5,-1) will ultimately move to (2,-1) after the reflection over x = -2.

Apply these steps to the other corner points and you'll end up with what is shown below.

Take note that a point like A(-5,-1) moves to A'(1,-1), and similar to the other points as well. Also, notice that when going from A to B to C, etc we are moving clockwise. We move counterclockwise when going from A' to B' to C' etc. Reflections always swap the orientation.

4 0
3 years ago
Which of the following equations has an infinite number of solutions?
Inessa [10]
It is 3x +5 = 2x -1 + x 
i hope that is was some sort of help you are welcome 
5 0
3 years ago
Order these numbers from least to greatest. 4.29 , −17 , −4.4 , −4711
Gre4nikov [31]
-4711, -17, -4.4, 4.29
7 0
4 years ago
Read 2 more answers
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