The answer to your question is <span>B.-2/3</span>
Answer:
I think it would be 4/2 wich eaquals 1/2
Step-by-step explanation:
Answer: 1
Step-by-step explanation:
Experimental probability is the actual result you get from an experement.
Theoretical probability is the change that you will get that result.
(for example: flipping a coin, the Theoretical probability is 50/50 but after testing the Experimental probability might be 47/53)
therefore,
1/6 is the Theoretical probability because you are using a six-sided number cube.
for the Theoretical probability and the Experimental probability to be the same, the fraction of the roll must equal 1/6.
1/6 equals 8/48.
therefore, since the numbers 1 and 6 were both rolled 8 times out of 48 they are consistant with the Theoretical probability of 1/6.
6 is not one of the answer choices listed so 1 must be your answer.
Yes, you can; based on the inherent assumption that the "two radicals that have negative values" are, in fact, "imaginary numbers" .
Take, for example, the commonly known "imaginary number": "i" ; which represents the "imaginary number" ; " √-1 " .
Since: "i = √-1" ;
Note that: " i² = (√-1)² = √-1 * √-1 = √(-1*-1) = √1 = 1 .
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Answer:
As per the question, we need to convert product of sum into sum of product,
Given:
(A' +B+C')(A'+C'+D)(B'+D'),
At first, we will solve to parenthesis,
= (A'+C'+BD) (B'+D')
As per the Rule, (A+B)(A+C) = A+BC, In our case if we assume X = A'+C', then,
(A' +B+C')(A'+C'+D) = (A'+C'+B)(A'+C'+D) = (A'+C'+BD)
Now,
= (A'+C'+BD) (B'+D') = A'B' + A'D' + C'B' +C'D' +BDB' +BDD"
As we know that AA' = 0, it mean
=A'B'+A'D'+C'B'+C'D'+D*0+B0
=A'B'+A'D'+C'B'+C'D' as B * 0 and D*0 = 0
Finally, minimum sum of product boolean expression is
A''B'+A'D'+C'B'+C'D'
=