Answer:
<h2>x = 3 and y = 4</h2>
Step-by-step explanation:
We know:
The diagonals in a parallelogram divide by halves.
Therefore KG = UG and DG = CG.
We have
KG = 5y - 8, UG = 3y, DG = 4x - 7, CG = x + 2
Substitute:
5y - 8 = 3y <em>add 8 to both sides</em>
5y = 3y + 8 <em>subtract 3y from both sides</em>
2y = 8 <em>divide both sides by 2</em>
y = 4
---------------
4x - 7 = x + 2 <em>add 7 to both sides</em>
4x = x + 9 <em>subtract x from both sides</em>
3x = 9 <em>divide both sides by 3</em>
x = 3
Answer:
It's really easy just remember rise over run.
Step-by-step explanation:
so you rise 3 and run to the right 3
A great tip that helps me determine if it's positive or neagitve is if you go to the left then it's ALWAYS neagtive but if you go to the right then it's ALWAYS postive
inaccurate
3 less than would be x-3, but 3-x would be 3 more
Answer:
3(n-5)=2n+16
Step-by-step explanation:
3 lots of 'n' <em>and </em>5 means 3 times both values so these values are put into a bracket with a common multiplier (ie. the 3)
3(5 - n)
16 more than 2 lots of 'n' means that n has to be doubled. n + n = 2n. add 16 to this and we have
2n + 16
if these values are both equal (hence why they are in an equation) then all that is needed is for them to be set equal alongside each other.
3(n-5) = 2n+16
:)
Answer:
-x+4
Step-by-step explanation:
-1(x-4) any expression multipled by 1 remains the same
-(x-4) remove the parenthesis
-x-4