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MaRussiya [10]
2 years ago
12

Please help if u see this

Mathematics
1 answer:
jek_recluse [69]2 years ago
7 0
<h3>Answer: Choice D</h3>

(f \circ g)(x) = x+12

Domain = [-3, infinity)

==================================================

Work Shown:

f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of (f \circ g)(x) as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

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1 BAJILLION POINTS!!
Natalija [7]

Answer:

False!

Step-by-step explanation:

As C is not equal to -13 (number line)

So, your answer would be false.

hope it helps!

4 0
3 years ago
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yanalaym [24]

Solve x+4y = 13 for x by subtracting 4y from both sides.

We end up with x = -4y+13.

Since x and -4y+13 are the same, we can replace every x in the first equation with -4y+13

2x-3y = -29

2( x ) - 3y = -29

2( -4y+13 ) - 3y = -29 ... x is replaced with -4y+13

The answer is choice B

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3 years ago
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Vinil7 [7]

Answer:

the answer is D pls brainliesttt

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liraira [26]

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