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3 years ago

Can someone do these 2 questions.

Mathematics

1 answer:

Airida [17]3 years ago

8 0

Answer:

Y= -4x + 6

Y = -3x/2 + 10

Step-by-step explanation:

not sure if I did it right sorry if not

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Which of the following is a counterexample that proves the conditional statement false?

Masja [62]

The answer is “A. 12” because 12 is NOT divisible by 8

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4 years ago

HELP! Here is the histogram of a data distribution. All class widths are 1.

Luden [163]

Answer:

Step-by-step explanation:

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3 years ago

The ages of two sisters are consecutive even integers. Twice the age of the youngest exceeds the oldest by 8. How old is the you

dezoksy [38]

Answer:

10 years old

Step-by-step explanation:

Let's say the age of the younger sister is x. Then the age of the older sister must be x + 2 because the ages are consecutive <em>even</em> numbers.

"Twice the age of the youngest exceeds the oldest by 8" means that we multiply x by 2 and set that equal to (x + 2) + 8:

2x = (x + 2) + 8

2x = x + 10

x = 10

So, the youngest sister is 10 years old.

8 0

3 years ago

Read 2 more answers

Please answer ASAP. The question is down below.

Butoxors [25]

Answer: 1) c 2) d

<u>Step-by-step explanation:</u>

Use Pythagorean Theorem to find the hypotenuse (r): x² + y² = r²

Given: x = 2, y = 6

2² + 6² = r²

4 + 36 = r²

40 = r²

$\sqrt{40}=r$

$\sin \theta=\dfrac{y}{r}\quad =\large\boxed{\dfrac{6}{\sqrt{40}}}\quad \rightarrow \dfrac{6}{2\sqrt{10}}\quad \rightarrow \dfrac{3}{\sqrt{10}}$

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$\sin \theta = \dfrac{opposite(y)}{hypotenuse(r)}\quad =\dfrac{12}{20}\quad \rightarrow \dfrac{3}{5}\quad \rightarrow \large\boxed{0.6}\\\\\\\cos \theta = \dfrac{adjacent(x)}{hypotenuse(r)}\quad =\dfrac{16}{20}\quad \rightarrow \dfrac{4}{5}\quad \rightarrow \large\boxed{0.8}$

5 0

3 years ago

A cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shif

omeli [17]

We have been given that a cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shift is 9 units down, and the period of the function is $\frac{7\pi}{12}$ . The graph of the function does not show a phase shift. We are asked to write the equation of our function.