Answer:
![\displaystyle \bar x=4\ sec](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbar%20x%3D4%5C%20sec)
Step-by-step explanation:
<u>Average Value
</u>
The mean or average of a number n of measurements is defined as the sum of all values divided by n.
![\displaystyle \bar x=\frac{\sum x_i}{n}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbar%20x%3D%5Cfrac%7B%5Csum%20x_i%7D%7Bn%7D)
The running times in seconds are being improved by the following numbers:
5, 3, 4
This is the dataset where we have to find the mean value. Here n=3. Applying the formula:
![\displaystyle \bar x=\frac{5+4+3}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbar%20x%3D%5Cfrac%7B5%2B4%2B3%7D%7B3%7D)
![\displaystyle \bar x=\frac{12}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbar%20x%3D%5Cfrac%7B12%7D%7B3%7D)
![\displaystyle \bar x=4\ sec](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbar%20x%3D4%5C%20sec)
Step-by-step explanation:
Angle W is the corresponds as to angle C
Answer:
Ai. Common ratio = 2/3
Aii. First term = 54
B. Sum of the first five terms = 422/3
Step-by-step explanation:
From the question given above, the following data were obtained:
3rd term (T3) = 24
6Th term (T6) = 64/9
First term (a) =?
Common ratio (r) =?
Sum of the first five terms (S5) =?
Ai. Determination of the common ratio (r).
T3 = ar²
T3 = 24
24 = ar²....... (1)
T6 = ar⁵
T6 = 64/9
64/9 = ar⁵......... (2)
The equation are:
24 = ar²....... (1)
64/9 = ar⁵......... (2)
Divide equation 2 by equation 1.
64/9 ÷ 24 = ar⁵ / ar²
64/9 × 1/24 = r³
8/27 = r³
Take the cube root of both side
r = 3√(8/27)
r = 2/3
Thus, the common ratio is 2/3
Aii. Determination of the first term (a).
T3 = ar²
3rd term (T3) = 24
Common ratio (r) = 2/3
First term (a) =?
24 = a(2/3)²
24 = 4a/9
Cross multiply
24 × 9 = 4a
216 = 4a
Divide both side by 4
a = 216/4
a = 54
Thus, the first term (a) is 54
B. Determination of the sum of the first five terms.
Common ratio (r) = 2/3
First term (a) = 54
Number of term (n) = 5
Sum of first five terms (S5) =?
Sn = a[1 –rⁿ] / 1 – r
S5 = 54[1 – (⅔)⁵] / 1 – ⅔
S5 = 54 [1 – 32/243] / ⅓
S5 = 54 (211/243) × 3
S5 = 54 × 211/81
S5 = 6 × 211/9
S5 = 2 × 211/3
S5 = 422/3
Thus, the sum of the first five terms is 422/3
Answer:
Your answer is: No solution
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Step-by-step explanation:
Hope this helped : )