Answer
C) 160 in^2
Step by step explanation
First, let's find the area of the rectangle.
Area of a rectangle = length x width
The area of the rectangle = 20 * 10
= 200 in^2
Now let's find the area of the triangle that is removed.
Area of a triangle = 1/2 base * height.
Here base = 10 and height = 8. Plug in these values into the formula, we get
Area of the triangle = 1/2 * 10*8
= 5* 8
The area of the triangle = 40 in^2
The area of the remaining figure = Area of the rectangle - area of the triangle
= 200 - 40
= 160 in^2
The answer is "160 in^2"
Thank you.
Answer:
do you have a picture
Step-by-step explanation:
Answer:
x = 5
Step-by-step explanation:
Solve for x:
2 (2 x - 5) = 3 x + x - 2 x
3 x + x - 2 x = 2 x:
2 (2 x - 5) = 2 x
Divide both sides by 2:
2 x - 5 = x
Subtract x from both sides:
(2 x - x) - 5 = x - x
2 x - x = x:
x - 5 = x - x
x - x = 0:
x - 5 = 0
Add 5 to both sides:
x + (5 - 5) = 5
5 - 5 = 0:
Answer: x = 5
Answer:
the Larger poster is 9ft long by 6ft wide
Step-by-step explanation:
In order to find the length and width values of the large poster we first need to find the width of the smaller poster since we are already given the length. Since we are also provided with the perimeter we can add the length twice and subtract it from the perimeter which would give us the value of both width sides of the rectangle, then we simply divide by 2 to get the value of the individual width.
10ft = 3ft + 3ft + w + w
10ft = 6ft + 2w
4ft = 2w
2ft = w
Since the larger poster is 3 times as big for the length and the width we simply multiply the smaller poster's length and width by 3...
L = 3 * 3 = 9ft
W = 2 * 3 = 6ft
Finally, we can see that the Larger poster is 9ft long by 6ft wide
