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WINSTONCH [101]
3 years ago
13

A $10 decrease followed by a $15 increase

Mathematics
1 answer:
Leto [7]3 years ago
3 0
That’s not the full question but if it was it would be greater bc 10 - 10=0 but 10-10+15 would equal 15 instead of 10
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Find the exact solution to the equation. Show your work for credit. (1 point) four to the power of quantity twelve minus four x
padilas [110]
4^(12-4x)=256  realize that 256 is 4^4  so we really have:

4^(12-4x)=4^4  taking the natural log of both sides

(12-4x)ln4=4ln4  dividing both sides by ln4

12-4x=4  subtract 12 from both sides

-4x=-8  divide both sides by -4

x=2


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3 years ago
WILL MARK BRANLIEST!!the tables below shows the values of y corresponding to different values of x
Kitty [74]

Answer: I'm pretty sure that it´s C but Im not sure.

Sorry if that's wrong.

7 0
3 years ago
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I NEED HELP ASAP PLSSS
Triss [41]

Answer:

y = x^2 - 4x - 5

y = (x + 1)(x - 5)

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Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck
Nimfa-mama [501]
\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}
\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}

Now, isolate the variables, so you can integrate.
(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}
\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}
2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C


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y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C
(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C
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y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}
y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}

At x = 1, y = 0.
0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}
-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}

4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0
\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}


4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C
0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C
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C = -\frac{\pi}{2}

\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}
6 0
3 years ago
How many solutions does the system of equations below have?
galben [10]

Answer:

C

Step-by-step explanation:

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