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3 years ago

Which expression is equivalent to 6/6

Mathematics

1 answer:

trapecia [35]3 years ago

3 0

Answer:

1/1 I think I hope this helps

Step-by-step explanation:

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Lourdes plans to jog at least 1.5 miles. Lourdes averages 3.75 mph pace when she jogs write and solve an inequality to find x, t

tamaranim1 [39]

Answer:

Step-by-step explanation:

At least means greater than or equal to, so that is the symbol we will use. Now, we want the inequality to compare the distance she plans to jog and the amount of time jogged multiplied by the speed, since time times speed equals distance.

Writing this out we get 1.5 ≤ 3.75x

so 1.5 will always be less than or equal to the distance jogged. let me know if there is something you don't understand. But after this just solve for x.

4 0

3 years ago

I need help asap plzz help

Art [367]

Answer: the answer is A! GOOD LUCK<3

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3 years ago

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For the line segment whose endpoints are X(1, 2) and Y(6, 7), find the x value for the

finlep [7]

Answer:

3) 2.7

Step-by-step explanation:

The distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ can be determined by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Since the points are X(1, 2) and Y(6, 7). The distance between the two points is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(6-1)^2+(7-2)^2}=\sqrt{50}$

the x value for the point located 1/3 the distance from X to Y,

$x=\frac{x_2-x_1}{3}=\frac{6-1}{3}=1.7$

The x value = $x_1+1.7 = 1+1.7 = 2.7$

6 0

3 years ago

Read 2 more answers

The isosceles triangle theorem says "If two sides of a triangle are congruent,

BartSMP [9]

Answer:

D. Draw KM so that Mis the midpoint of JL, then prove AJKM * A

LKM using SAS.

8 0

3 years ago

The bar graph to the right shows the average number of hours that people sleep per day by age group use this information to comp

aleksklad [387]

We must write the relation between the age and the average number of hours slept as a set of ordered pairs.

Notice that the average number of hours slept by age is the following:

$\begin{gathered} 17\text{ years}\rightarrow9.4\text{ hours} \\ 22\text{ years}\rightarrow9.2\text{ hours} \\ 35\text{ years}\rightarrow8.8\text{ hours} \\ 45\text{ years}\rightarrow8.9\text{ hours} \\ 55\text{ years}\rightarrow8.5\text{ hours} \\ 65\text{ years}\rightarrow8.2\text{ hours} \end{gathered}$

To write the function as a set of ordered pairs, use the data from the domain (years) and from the range (hours) to form ordered pairs as (years,hours).

Then, the function as a set of ordered pairs is:

$\mleft\lbrace(17,9.4\mright),(22,9.2),(35,8.8),(45,8.9),(55,8.5),(65,8.2)\}$

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2 years ago